2. For a solution equimolar in HCN and NaCN, which statement is false? a. This is...

Question

Question

2. For a solution equimolar in HCN and NaCN, which statement is false?

a. This is an example of the common ion effect.

b. The [H+] is larger than it would be if only the HCN was in solution.

c. The [H+] is equal to the Ka.

d. Addition of more NaCN will shift the acid dissociation equilibrium of HCN to the left.

e. Addition of NaOH will increase [CN–] and decrease [HCN].

please explain option B and C

Answer 1

Answer #1

Answer 2

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