Question

Demonstrate the central dogma using the following short DNA sequence. Upper cases denote exons, lower cases...

Demonstrate the central dogma using the following short DNA sequence. Upper

cases denote exons, lower cases introns (the gene is on the upper strand). Basically

you perform DNA replication on the sequences, label the child and parent strands,

conduct transcription of the sequence (i.e., DNA–

>

mRNA, no need to do the cap-

ping and addition of poly-A tails), then translation of the sequence (30 points).

5’ctaagATGCCGATgtttaaaagACTAAAAGTTAAgtttcacagTTCAGGGCAACGGCGGTGAgtaaaa3’

3’gattcTACGGCTAcaaattttcTGATTTTCAATTcaaagtgtcAAGTCCCGTTGCCGCCACTcatttt5’

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Answer #1

Given DNA sequence,

5’ ctaagATGCCGATgtttaaaagACTAAAAGTTAAgtttcacagTTCAGGGCAACGGCGGTGAgtaaaa 3'

3’ gattcTACGGCTAcaaattttcTGATTTTCAATTcaaagtgtcAAGTCCCGTTGCCGCCACTcatttt 5’

After replication, two double stranded DNA molecules will be formed,

5’ ctaagATGCCGATgtttaaaagACTAAAAGTTAAgtttcacagTTCAGGGCAACGGCGGTGAgtaaaa 3’ (parental strand)

3’ gattcTACGGCTAcaaattttcTGATTTTCAATTcaaagtgtcAAGTCCCGTTGCCGCCACTcatttt 5’ (daughter strand)

And the other DNA molecule will be,

3’ gattcTACGGCTAcaaattttcTGATTTTCAATTcaaagtgtcAAGTCCCGTTGCCGCCACTcatttt 5’ (parental strand)

5’ ctaagATGCCGATgtttaaaagACTAAAAGTTAAgtttcacagTTCAGGGCAACGGCGGTGAgtaaaa 3’ (daughter strand)

After transcription, the DNA strand in 3' to 5' direction will form mRNA in the 5' to 3' direction,

DNA strand 1,

3’ gattcTACGGCTAcaaattttcTGATTTTCAATTcaaagtgtcAAGTCCCGTTGCCGCCACTcatttt 5’ (daughter strand)

mRNA will be,

5' cuaagAUGCCGAUguuuaaaagACUAAAAGUUAAguuucacagUUCAGGGCAACGGCGGUGAguaaaa 3'

Removal of introns and joining of exons,

5' AUG CCG AUA CUA AAA GUU AAU UCA GGG CAA CGG CGG UGA 3'

Amino acid formed after translation in mRNA,

N met pro ile leu lys val asn ser gly gln arg arg STOP C

DNA strand 2,

3’ gattcTACGGCTAcaaattttcTGATTTTCAATTcaaagtgtcAAGTCCCGTTGCCGCCACTcatttt 5’ (parental strand)

mRNA formed after transcription,

5'

cuaagAUGCCGAUguuuaaaagACUAAAAGUUAAguuucacagTTCAGGGCAACGGCGGUGAguaaaa 3'

Removal of introns and joining of exons

5'

AUG CCG AUA CUA AAA GUU AAT TCA GGG CAA CGG CGG UGA 3'

Amino acids formed after translation,

N met pro ile leu lys val asn ser gly gln arg arg STOP C

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