Sawsan mass is 50 kg. What is the electric field required to suspend Sawsan in mid-air...

Question

Question

Sawsan mass is 50 kg. What is the electric field required to suspend Sawsan in mid-air if Sawsan carries a charge of 0.001 coulomb?
If Sawsan and her identical twin are in space, what is the acceleration of Sawsan towards her twin if the separation distance between them is 1 m

Answer 1

Answer #1

a) Sawsan will be suspended when the electric field cancels the weight.

qE = mg

the electric field required to suspend Sawsan in mid-air is

b) The net force of Sawsan towards her twin is gravitational attraction - electrostatic repulsion

The acceleration of Sawsan towards her twin if the separation distance between them is 1 m is

a = F/m

Therefore

The acceleration is negative which means Sawsan and her twin are moving away because electrostatic repulsion

Answer 2

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