A hungry 181 kg lion running northward at 84.5 km/hr attacks and holds onto a 38.6 kg Thomson's gazelle running eastward at 57.4 km/hr. Find the final speed of the lion–gazelle system immediately after the attack. final speed: m/s
Solution)
Applying law of conservation in the north direction,
181 kg* 84.5 km/hr= (181 kg +38.6 kg)*Vy
So, Vy= 69.64 km/hr
Now, applying law of conservation in east direction
38.6 kg*57.4 km/hr= (181 kg + 38.6 kg)* Vx
Vx= 10.08 km/hr
Now,
Velocity, v=sqrt(vx^2 +vy^2)=sqrt(10.08^2 + 69.64^2)= 70.36 km/hr
Direction, tan theta= 69.64/10.08
Theta= 81.76 degrees north of east
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A hungry 181 kg lion running northward at 84.5 km/hr attacks and holds onto a 38.6...
Lions can run at speeds up to approximately 80.0 km/h. A hungry 110 kg lion running northward at top speed attacks and holds onto a 36.5 kg Thomson's gazelle running eastward at 79.5 km/h. Find the final speed up of the lion-gazelle system just after the lion attacks. Uf = m/s Find the angle between the final velocity of the lion-gazelle system and the East axis, with positive angles measured counterclockwise from the East axis. =
I got 17.51 for the first answer but it's telling me that it's
wrong. Can anyone help me, please?
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