I got 17.51 for the first answer but it's telling me that it's wrong. Can anyone help me, please?
the answer is one of this.please go through the concept .the second one is through the conservation of momentum concept that is
let the mass of lion is M and mass of gazelle is m then
Mx80+mx75=(M+m)v
the velocity after the collision is the same because after collision they are a single mass that is a single unit.
if any doubt, please ask me in the comment section
I got 17.51 for the first answer but it's telling me that it's wrong. Can anyone help me, please?
Lions can run at speeds up to approximately 80.0 km/h. A hungry 110 kg lion running northward at top speed attacks and holds onto a 36.5 kg Thomson's gazelle running eastward at 79.5 km/h. Find the final speed up of the lion-gazelle system just after the lion attacks. Uf = m/s Find the angle between the final velocity of the lion-gazelle system and the East axis, with positive angles measured counterclockwise from the East axis. =
A hungry 181 kg lion running northward at 84.5 km/hr attacks and holds onto a 38.6 kg Thomson's gazelle running eastward at 57.4 km/hr. Find the final speed of the lion–gazelle system immediately after the attack. final speed: m/s