What is the energy of a photon of light of wavelength 0.90 µm?
Solution)
Given,
Wavelength, lambda=0.9*10^-6 m
We know, Energy, E= hc/lambda
Substitute values,
E=(6.626*10^-34)*(3*10^8)/(0.9*10^-6)
E= 2.20*10^-19 J (Ans)
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