Add comments on this Fibonacci C++ program in detail.
#include <iostream> using namespace std; int fib(int n){ int a = 0,b = 1,c; if(n == 0 || n == 1){ return n; } while(n>2){ c = b + a; a = b; b = c; n--; } return c; } int main(){ int n; cout<<"Enter n: "; cin>>n; int result = fib(n); cout<<"Fib("<<n<<") = "<<result<<endl; return 0; }
#include <iostream> using namespace std; int fib(int n) { int a = 0, b = 1, c; if (n == 0 || n == 1) { // if n is 0 or 1, then return n. because fibonacci of 0 is 0 and fibonacci of 1 is 1 return n; } while (n > 2) { // as long as n is greater than 2 // a and b are fibonacci numbers // set a to b // and set b to sum of previous two terms c = b + a; // calculate fibonacci of next number. fibonacci of n is sum of previous two fibonacci numbers a = b; // set a to b b = c; // set b to sum of previous two terms which is stored in c n--; // decrement value of n } return c; // return the calculated fibonacci number } int main() { int n; cout << "Enter n: "; // ask user to enter a number cin >> n; // read a number int result = fib(n); // determine fibonacci of n cout << "Fib(" << n << ") = " << result << endl; // print fibonacci of n to screen return 0; }
Add comments on this Fibonacci C++ program in detail. #include <iostream> using namespace std; int fib(int...
How do can I update this code (Code A): Code (A) #include using namespace std; int fibonacci(int n) { int a = 0, b = 1, c; if (n <= 1) return n; for (int i = 2; i <= n; i++) { c = a + b; a = b; b = c; } return b; } int fibonacciRecursive(int n) { if (n <= 1) { return n; } return fibonacciRecursive(n-1) + fibonacciRecursive(n-2); } int main() { int n;...
Consider the following C++ program: #include <iostream> #include <cstdlib> using namespace std; int main int n =0; int i = 0; cout << "Please enter a strictly positive number:"; cin >> n if (n <= 0) exit(EXIT_FAILURE) while (n > 1) n-n/2; i << endl; cout"Output:" return 0; Answer the following questions: What is the output of the program for each of the following values of n: -1, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9? What does...
#include <iostream> #include <string> using namespace std; int main() { int number; int sum = 0; while(true) { cout << "Please enter a number between 1 and 11: "; cin >> number; if (number >= 1 && number <= 11) { cout << number << endl; sum = sum + number; //only add the sum when number is in range: 1-11, so add wthin this if case } else { cout << number << endl; cout << "Out of range;...
#include <iostream> #include <conio.h> #include<limits> using namespace std; int main(){ char oparand, ch = 'Y'; int num1, num2, result; while(ch == 'Y'){ cout << "Enter first number: "; cin >> num1; while(1){//for handling invalid inputs if(cin.fail()){ cin.clear();//reseting the buffer cin.ignore(numeric_limits<streamsize>::max(),'\n');//empty the buffer cout<<"You have entered wrong input"<<endl; cout << "Enter first number: "; cin >> num1; } if(!cin.fail()) break; } cout << "Enter second number: "; cin >> num2; while(1){ if(cin.fail()){ cin.clear(); cin.ignore(numeric_limits<streamsize>::max(),'\n'); cout<<"You have entered wrong input"<<endl; cout <<...
Write following program using Switch statement. #include <iostream> using namespace std; int main() int number; cout << "Enter an integer cin >> number; if (number > B) cout << You entered a positive integer: " << number << endl; else if (number (8) cout<<"You entered a negative integer: " << number << endl; cout << "You entered e." << endl; cout << "This line is always printed." return 0;
Find two syntax errors in the following program: #include <iostream> using namespace std; int area(int length, int width = 0); int main() { int length, width; // for rectangle use both arguments cout << "Enter length and width of a rectangle" << endl; cin >> length >> width; cout << "The area is " << area(length, width) << endl; // for square, only need first argument cout << "Enter side of a square" << endl; cin >> length; cout <<...
#include <iostream> #include <chrono> using namespace std; double improvedPow(double x, int y) { // To be implemented by you } int main() { cout << "To calculate x^y ..." << endl; double x; int y; cout << "Please enter x: "; cin >> x; cout << "Please enter y: "; cin >> y; if(x == 0) { if (y > 0) cout << 0 << endl; else cout << "x^y is not defined" <<endl; } else { cout << improvedPow(x,y)...
#include <iostream> using namespace std; int main() { int sumOdd = 0; // For accumulating odd numbers, init to 0 int sumEven = 0; // For accumulating even numbers, init to 0 int upperbound; // Sum from 1 to this upperbound // Prompt user for an upperbound cout << "Enter the upperbound: "; cin >> upperbound; // Use a loop to repeatedly add 1, 2, 3,..., up to upperbound int number =...
what is the output for the following code? explain the steps. /*#include <iostream> using namespace std; int f(int &i) { i = 10; return(5 * i); } int main() { int n = 5; f(n); cout << n << "\n"; return 0; } #include <iostream> using namespace std; int sub1(int n) { n--; return n; } int main() { int m = 10; for(int j = 0; j < 10; j++) m -= sub1(j); cout << m << "\n"; return...
Write the missing statements for the following program. #include <iostream> using namespace std; int main(void) { int Num1; cout << "Enter 2 numbers: "; cin >> Num2; if (Num1 < Num2) cout << "Smallest number is " << Num1; else cout << "Smallest number is " << Num2; return 0; }