The latest poll for Obama v. Romney in Presidential Election 2012 shows that 47% will vote...
The latest poll for Obama v. Romney in Presidential Election 2012 shows that 47% will vote for Obama and 43% will vote for Romney, while the rest are still undecided.
a. Of 50 voters, find the expected number of votes for Obama.
b. Of 50 people, find the standard deviation of the number of votes for Romney.
c. Find the probability that, of 15 votes, at least 7 of them will be for Obama.
d. Find the probability that any of those 15 voters is still undecided.
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The latest poll for Obama v. Romney in Presidential Election
2012 shows that 47% will vote...
The November 2012 Presidential Election had Barack Obama and Mitt Romney as the 2 major candidates....
The November 2012 Presidential Election had Barack Obama and Mitt Romney as the 2 major candidates. Suppose that 2/3 of the people in the city supported Obama but 5/9 of the people in the suburbs supported Romney. 60% of the people live in the city while 40% of the people live in the suburbs. If you select a random Obama supporter, what is the probability that this person lives in the city?
Question 20 In the 2012 presidential election, exit polls from the critical state of Ohio provided...
Question 20 In the 2012 presidential election, exit polls from the critical state of Ohio provided the following results: Total Obama Romney 4590 no college degree (60%) college graduate (40%) 52% 47% 51% What is the probability a randomly selected respondent voted for Obama? Give the exact answer. exact number, no tolerance
In the 2012 presidential election, exit polls from the critical state of Ohio provided the following...
In the 2012 presidential election, exit polls from the critical state of Ohio provided the following results: Obama Romney No college degree (60%) College graduate (40%) 52% 47% 45% 51% If a randomly selected respondent voted for Obama, what is the probability that the person has a college degree? Round your answer to 3 decimal places (e.g. 0.987)
A random sample of 500 voters was taken after the 2012 presidential election, and the following...
A random sample of 500 voters was taken after the 2012 presidential election, and the following table was produced comparing support for Barack Obama and Mitt Romney across minorities and non-minorities. RomneyvsObamaSupport.PNG Use the appropriate test to determine whether the results are independent or dependent with 95% confidence while answering questions 24-26 below.What is the null hypothesis? What is the research hypothesis? You may use either mathematical notation, or express it in words.
Questions A-C a) In the 2012 Presidential Election Barack Obama received 51.1% of all votes cast....
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In a survey of 1425 people, 1045 people said they voted in a recent presidential election....
In a survey of 1425 people, 1045 people said they voted in a recent presidential election. Voting records show that 71% of eligible voters actually did vote. Given that 71% of eligible voters actually did vote, (a) find the probability that among 1425 randomly selected voters, at least 1045 actually did vote. (b) What do the results from part (a) suggest?
In a survey of 13181318 people, 877877 people said they voted in a recent presidential election....
In a survey of 13181318 people, 877877 people said they voted in a recent presidential election. Voting records show that 6464% of eligible voters actually did vote. Given that 6464% of eligible voters actually did vote, (a) find the probability that among 13181318 randomly selected voters, at least 877877 actually did vote. (b) What do the results from part (a) suggest?
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1107 people, 816 people said they voted in a recent presidential election. Voting records show that 71% of eligible voters actually did vote. Given that 71% of eligible voters actually did vote, (a) find the probability that among 1107 randomly selected voters, at least 816 actually did vote. (b) What do the results from part (a) suggest? (a) P(X ≥816) ? round 4 decimals
In a survey of 1127 people, 739 people said they voted in a recent presidential election....
In a survey of 1127 people, 739 people said they voted in a recent presidential election. Voting records show that 63% of eligible voters actually did vote. Given that 63% of eligible voters actually did vote, (a) find the probability that among 1127 randomly selected voters, at least 739 actually did vote. (b) What do the results from part (a) suggest? (a) P(x≥739) = b) What does the result from part (a) suggest? A.People are being honest because the probability...
Question 20 In the 2012 presidential election, exit polls from the critical state of Ohio provided the following results: Total Obama Romney 4590 no college degree (60%) college graduate (40%) 52% 47% 51% What is the probability a randomly selected respondent voted for Obama? Give the exact answer. exact number, no tolerance
In the 2012 presidential election, exit polls from the critical state of Ohio provided the following results: Obama Romney No college degree (60%) College graduate (40%) 52% 47% 45% 51% If a randomly selected respondent voted for Obama, what is the probability that the person has a college degree? Round your answer to 3 decimal places (e.g. 0.987)
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