During a national debate on changes to health care, a cable news service performs an opinion poll of 520 small-business owners. It shows that 41% of small-business owners do not approve of the changes.
Develop a 99% confidence interval for the proportion opposing health care changes. (Round your answers to 4 decimal places.)
Do majority approve?
No
Yes
99% confidence interval for p is
-
Z
/2 * sqrt
(
( 1 -
) / n) <
p <
+
Z
/2 * sqrt
(
( 1 -
) / n)
0.41 - 2.5758 * sqrt( 0.41 * 0.59 / 520) < p < 0.41 + 2.5758 * sqrt( 0.41 * 0.59 / 520)
0.3544 < p < 0.4656
99% confidence interval for p is (0.3544 , 0.4656)
Since 0.50 does not contain in confidence interval, we have sufficient evidence to support the claim
that majority approve.
Yes
During a national debate on changes to health care, a cable news service performs an opinion...
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During a national debate on changes to health care, a cable news service performs an opinion poll of 500 small- business owners. It shows that 65 percent of small-business owners do not approve of the changes. Develop a 95 percent confidence interval for the proportion opposing health care changes. Comment on the result
i started it but then i got lost, please correct me if im wrong!
also, include sketch, thank u :)
During a national debate on changes to health care, a cable news service performs an opinion poll of 500 small business owners. It shows that 65% of small-business owners do not approve of health care changes. Develop a 95% confidence interval for the proportion opposing health care changes. Use 4 decimal places. Answers Point Estimate 0.65 0.65 Standard Error 0.04...
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