Question

code a program with a while loop which allows a user to enter i tegers and pront their average when the suer enters 0

Answer 1

/*

Program executed using Dev c++ on windows operating system

*/

#include<iostream>
using namespace std;
int main(){
   //declaration of varibale
   int n,i;
   double num,average,sum;
   //intialized varibles
   sum=0;
   average=0;
   i=0;//intialized i to zero
   cout<<"Enter Count for numbers::";
   cin>>n;
   // loop for accept n numbers
   while(i<n){
       //accept number
       cout<<"\n Enter number "<<i+1<<"::";
       cin>>num;
       // add all number into sum
       sum=sum+num;
       i=i+1;
      
   }
   //if n is positive then print result
   if(n>0){
           average=sum/n;
            cout<<"\n Avarage of entered number is ::"<<average;
   }
   // wrong count or negtive count
   else{
       cout<<"\n User Enter Zero count or negative count for number ";
   }

  
}

/*

output

Enter Count for numbers::4

Enter number 1::210

Enter number 2::141

Enter number 3::201

Enter number 4::41

Avarage of entered number is ::148.25
--------------------------------
Process exited after 9.541 seconds with return value 0
Press any key to continue . . .

*/

//Some screen shot