For a traverse grinding on a horizontal surface grinder. The cross feed per cutting stroke is...
For a traverse grinding on a horizontal surface grinder. The cross feed per cutting stroke is 20 mm/stroke. The depth of the cut is 40 mm. The traverse speed is 10 mm/min.
Find the metal removal rate (mm3/min)?
Homework Answers
Given,
cross feed per cutting stroke(f) =20mm/stroke
depth of cut(d) =40mm
traverse speed(v)= 10mm/min
metal removal rate(mm^3/min) = f*d*v (* indicates multiplication)
M.R.R = 20*40*10 =8000mm^3/min
Therefore , for min in traverse grinding 8000 mm^3 volume of material is removed .
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