assume that a procedure yield a binomial distribution with 2 trials and a probability of success of 0.90. use a binomial probability table to find the probability that the number of success is exactly 0. The probability that the number of success is exactly 0 is?
Let X be a binomial random variable with n = 2 and p = 0.90
X ~ Binomial ( n = 2, p = 0.90)
Probability mass function of X is,
P(X = x) = nCx px (1 - p)n-x
We want to find, P(X = 0)
P(X = 0)
= 2C0 * (0.90)0 * (1 - 0.90)2-0
= 1 * 1 * (0.10)2
= 0.01
Therefore, the probability that the number of success is exactly 0 is 0.01
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