Question

A ball is thrown straight upward and returns to the thrower's hand after 2.30 s in...

A ball is thrown straight upward and returns to the thrower's hand after 2.30 s in the air. A second ball is thrown at an angle of 39.0° with the horizontal. At what speed must the second ball be thrown so that it reaches the same height as the one thrown vertically?

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Answer #1

Concept - use equation of kinematics to find the maximum height for the first ball and use that to find the required speed for the second one as shown below

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