Question

Part A: The confidence interval of population proportion obtained from x = 120 and n = 500 at the 99% level of confidence

Part B: what is the margin of error in ±%

a. 24%±5%

b. 24% ± 2.5%

c. 24%±1%

d. 5%±24%

e. 99% ± 24%.

Answer 1

For 99% confidence, z = 2.576

Sample proportion = 120/500 = 0.24

Hence,

Margin of error = = 0.049 = 5%

So,

24%±5%

Option A is correct.