Answer: According to Bernoulli's principle, the pressure at a point in a static fluid is transmitted equally throughout the fluid undiminished.
Now, in a hydraulic lift, we use this to our advantage by placing two cylinders of different cross-sectional areas on a static fluid. Then we apply force f on the smaller cylinder of area a, which gives pressure P=f/a.
Since the pressure is constant in the static fluid, the pressure reverted back on the large cylinder will incur a higher force, since
P=F/A=f/a
So, F=f/a * A = 180/(*1*1) * (*15*15) = 40500 N
Now, the 40500 N of force can only sustain/lift a mass whose weight is less than equal to 40500 N
So, the maximum mass possible is 40500/g = 40500/9.8 = 4132.65 Kg
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