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This is linear systems and digital signal processing.

Please answer this question with clean handwriting.

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Δ Moing to another question will save this response. Question 2 of 23 2] <<< Question 2 5 points Save Answer Consider the following MATLAB code using the handel.mat example file that comes with MATLAB:>load handel: >>ys y(1000:1000+100:X SpectrumAnalysis(ys,Fs,2412); where SpectrumAnalysis is a user defined function that computes an N-point FFT (G.e. 2412 points), to an input signal ys with a sampling frequency Fs. Which of the following statements about the spectrum of ys is correct? 1. The main spectral peak is located around 1064 Hz and our computation resolution is of 2 Hz. O 2. The main spectral peak is located around 546 Hz and our computation resolution is of 4 Hz. O 3. The main spectral peak is located around 546 Hz and our computation resolution is of 1 Hz O 4. The main spectral peak is located around 546 Hz and our computation resolution is of 2 Hz. O 5. The main spectral peak is located around 1064 Hz and our computation resolution is of 1 Hz Moving to another question will save this response. K K Question 2 of 23 2 Close Window 3-DSP-Intervie....df Show All

Answer 1

After getting ys, we have ys as 101 samples with Fs = 8096 Hz.

Now we want to take FFT of size 2^12, then the spectrum of ys i.e from (-4096) Hz to 4095 Hz is divided into 2^12(=4096) points.

Therefore, the frequency resolution = 2*4096/2^12 = 2 Hz.

The spectrum of ys is given below generated from Matlab:-

3.5 X: 546 Y: 3.032 2.5 2 1.5 0.5 0 -5000 -4000 -3000 -2000 -1000 0 1000 2000 3000 4000 5000 Frequency (Hz)

From the figure, we can locate the peak at 546 Hz.

Therefore the answer is 4. The peak at 546 Hz with computation resolution of 2 Hz.