1. For the following three-phase network, draw the positive sequence diagram and the zero sequenc...
The component parameters for the power system shown in Figure 2 are given in Table 1. The pre-fault voltage is 120° pu and Zx-j0.1 pu. Table 1 Ratings X2-Xi (pu)Xo (pu) 0.05 0.10 0.20 0.20 Components G1, G2 200 MVA, 20 kV 0.10 0.10 0.10 0.10 T1, T2, T3200 MVA, 20/200 kV L1 200 MVA, 200 kV し2 200 MVA, 20 kV (a) Draw the three sequence networks and determine the per-unit Thevenin impedance of each sequence network seen from...
can you calculating this question and explain why? thanks The ratings and sequence reactances of the components for the power system shown in Figure 2 are given in Table 1. The pre-fault voltage is 1/0° per unit (pu). Bus 8 L3 Bus 1 T1 Bus 4 T2 Bus 2 Bus 5 L1 L2 G1 Bus 3 T3 Bus 7 Bus 6 D.6975 Figure Draw the per unit impedance sequence networks and determine the per unit (a) Thevenin impedances of the...
A single line diagram of a power system is shown in Fig. 2. The system data with equipment ratings and assumed sequence reactances are given the following table. The neutrals of the generator and A-Y transformers are solidly grounded. The motor neutral is grounded through a reactance Xn 0.05 per unit on the motor base. Assume that Pre-fault voltage is takin as VF-1.0 ,0° per unit and Pre- fault load current and Δ-Y transformer phase shift are neglected In the...
The equipment ratings for a five bus system are given as Generator G1: 50 MVA, 12 kV, Xd ’’=X2=0.20, X0= 0.10 per unit Generator G2: 100 MVA, 15 kV, Xd ’’=0.2, X2=0.23, X0= 0.10 per unit Transformer T1: 50 MVA, 10 kV (Y)/138 kV (Y), X=0.10 per unit Transformer T1: 100 MVA, 15 kV (∆)/138 kV (Y), X=0.10 per unit Each 138 kV line: X1=40 Ohms, X0=100 ohms (1) Draw out the zero-, positive-, and negative- sequence reactance diagrams for the original system using a 100-MVA,...
A simple three-phase power system is shown in Figure 2. Assume that the ratings of the various devices in this system are as follows: • Generators G1, G2: 40 MVA, 13.2 kV, = 0.15 pu, = 0.15 pu, = 0.08 • Generator G3: 60 MVA, 13.8 kV, = 0.20 pu, 0.20 pu, - 0.08 • Transformers T1, T2, T3, T4: 40 MVA, 13.8/138 kV, X1 = X2 = 0.10 pu, XO 0.08 pu Transformers T5, T6: 30 MVA, 13.8/138 kV, X1 = X2...
3) The single-line diagram of a three-phase power system is shown in Fig. 1. Equipment ratings are given as follows: G1 1,000 MVA, 15.0 kV, 20.18, o 0.07 pu G2 : 1,000 MVA. 15.0 kV, 攻=エ1 =エ2 = 0.20, ro = 0.10 pu G3 : 500 MVA, 13.8 kV. 1" = 띠 z2 = 0.15, zo 0.05 pu G4 : 750 MVA, 13.8 kV. ェd =ェ1 = 0.30, T2 = 0.40 ro = 0.10 pu Ti : 1,000 MVA. 15.0Δ/765Y...
2. nBase MVA 100p LI Base KV G1 20kV Base KV Lines 220kv G13 phase 20 kv, 100 MVA Xd-1, Xd-0.3, Xd"-0.2, Xo-0.8 H-1s T1 3 phase 100 MVA20kv -220kv, DY,X-0.1 L1, L2 Ro X1-0.2 pu on given base Y ignored L2 The infinite bus voltage is 1 PU The generator supplies 0.6 pu real power at 0.8 pf lagging to the infinite bus a. Sketch an impedance diagram appropriate for transient stability analysis b. Calculate the internal transient voltage...
3.13 A single-line diagram of a three-phase power system is shown in Fig. 3.51. The ratings of the equipment are shown below Generator G: 100 MVA, 11 kV, Xi -X2-0.20 pu, Xo -0.05 pu Generator G2 : 100 MVA, 20 kV, Xi=X2=0.25 pu, Xo=0.03 pu, X,,-0.05 pu Transformer T: 100 MVA, 11/66 kV, Xi -X2-Xo 0.06 pu Transformer T2: 100 MVA, 11/66 kV, Xi-X2 = Xo 0.06 pu Line: 100 MVA, X,-X2 = 0.15 pu, Xo = 0.65 pu A...
2. Three generators feed a 2-transmission line network (see below). Each component of the network is expressed in per-unit on its own power and voltage rating 100 MVA 138 kV 14 0.03 Bus 1 Bus 4 100 MVA 138 kV XL24 = j0.02 Bus 2 2 50 MVA 13.2 KV G10.1 pu XT0.2 pu 50 MVA 132/13.2 kV 100 MVA 138/20 kV XT2uX2 0.1 pu 100 MVA 18 kV 35 MVA 132/13.2 kV XT3 = 0.2 pu Bus 3 20...
Q3: (15 Points) Equi below are given as follows: pment ratings and per-unit reactances for the system shown in circuit 2 4 T1 TL12 T2b G1 G2 TL13 TL23 0.03 j0.03 Synchronous Generators: G1 100 MVA 25 kV G2 100 MVA 3.8 kV Transformers: T1 100 MVA 25/230 kV T2 100 MVA 13.8 /230 kV X1=X2= 0.2 X0-0.05 X1-X2-0.2 X0 0.05 X1 = X2-X0 = 0.05 Transmission lines: TL12 100 MVA TL13 100 MVA TL23 100 MVA X0 0.3 XO...