He second form for one-parameter exponential family distributions, introduced during lecture 09.1...
Show that the following distributions belong to the exponential family. Find the natural parameter θ, scale parameter p and convex function b(9). Also find the E(Y) and Var(Y) as functions of the natural parameter. Specify the canonical link functions 1. Exponential distribution Bxp ), f(y:λ) λe-Ag. Binomial distribution known; f(y: π- C)π"(1-π)n-y, where n is 2. Bin(n,π). 3. Poisson distribution Pois(A), f(y:A)-e
Return to the original model. We now introduce a Poisson intensity parameter X for every time point and denote the parameter () that gives the canonical exponential family representation as above by θ, . We choose to employ a linear model connecting the time points t with the canonical parameter of the Poisson distribution above, i.e., n other words, we choose a generalized linear model with Poisson distribution and its canonical link function. That also means that conditioned on t,...
Show that the family of distributions GAM , к): > 0, к > 0 belongs to the regular exponential class, and use this information to find com plete sufficient statistics based on a random sample Xi,... , X, Let Xi,... , Xn be a random sample from a Bernoulli distribution, Xi BIN(1,p):0<p1. EX)-Σ x, n(n -1) Verify that T- is an unbiased estimator of p Then show that T is a UMVUE of p2 Show that the family of distributions...
would this not be a two parameter exponential family? if not why not im struggling to understand (a) We can write the density as fe(y) v2rez exp{-282 (y – 0)2} exp{-} log(20) – į log(02) – 2 +% – }} = We are not able to identify c(O), T(y), d(0), S(y) as this form exp{c(0)T(y) + d(0) + S(y)} This shows that this distribution does NOT belong to the exponential family.
In this problem, we will model the likelihood of a particular client of a financial firm defaulting on his or her loans based on previous transactions. There are only two outcomes, "Yes" or "No", depending on whether the client eventually defaults or not. It is believed that the client's current balance is a good predictor for this outcome, so that the more money is spent without paying, the more likely it is for that person to default. For each x,...
I. Let X be a random sample from an exponential distribution with unknown rate parameter θ and p.d.f (a) Find the probability of X> 2. (b) Find the moment generating function of X, its mean and variance. (c) Show that if X1 and X2 are two independent random variables with exponential distribution with rate parameter θ, then Y = X1 + 2 is a random variable with a gamma distribution and determine its parameters (you can use the moment generating...
Practice problems using various statistical methods If n independent random variables X have normal distributions with means μ and the standard deviations σ , then determine the distribution of a. I. X-E(X) var(X) C. 2. If n independent random variables Xi have normal distributions with means μί and the standard deviations σί, then determine the distribution of a. b. Y -a1X1 + a2X2+ + anXn (ai constant) X-E(X) Vvar(X) 3. What is CLT? Proof briefly? What are t-, Chi-squared- and...
Consider a random sample of size n from a two-parameter exponential dist EXP(e, n). Recall from Exercise 12 that X 1 ., and X are jointly sufficient for O Because Xi:n is complete and sufficient for η for each fixed value of θ, argue from 104.7 that X, and T X1:n X are stochastically independent. ibution, X, 30. Theor (a) Find the MLE θ of θ. (b) Find the UMVUE of η. (c) Show that the conditional pdf of Xi:n...
11. Chi-Squared Test for a Family of Discrete Distributions A Bookmark this page In the problems on this page you will apply the goodness of fit test to determine whether or not a sample has a binomial distribution So far, we have used the x test to determine if our data had a categorical distribution with specific parameters (e.s uniform on an set). element For the problems on this page, we extend the discussion on x tests beyond what was...
One side concept introduced introduced in the second Bayesian lecture is the conjugate prior. Simply put, a prior distribution π (0) is called conjugate to the data model, given by the likelihoodfunction L (Xi θ if the posterior distribution π (ex 2, , . , X ) is part of the same distribution family as the prior. This problem will give you some more practice on computing posterior distributions, where we make use of the proportionality notation. It would be...