Calculate the equilibrium constant for the following reaction at 25 °C and 150°C. 11. (2) NH CI()...
QUESTION 12 Given that AG for NH=-16.667999999999999 kJ/mol, calculate the equilibrium constant for the following reaction at 298 K: N2(8)+3 H2()2 NH3(g) Oa5.820000000000003 x 108 b8 349999999999996 x 102 Oc1.01 Od696999 998 x 10s O4.5099999999999998 x <1069
step by step for both please T71 pts Consider the reaction: NH, (g) + HCI (9) ► NH,CI (s) Given the following table of thermodynamic data at 298 ok: Substance by admons Imoly NH HCI NHCI 4 6.19 -92.30 -314.4 192.5 186,69 94.6 The value of K for the reaction at 25°C is 150 1.4 x 10 1.1 x10-16 9.3 x1095 8.4 x109 Question 2 1/1 pts The equilibrium constant for the following reaction is 5.0 x 10% at 25°C....
e. 2.89 Calculate the thermodynamic equilibrium constant at 25°C for a reaction for which Δσ.-2560 kJ per mol of reaction:R-8.314 J/mol K a. 5.14 ×101 42. 6.12 × 102 3.07 x 104 d) e. 4.32 x 10 -t も
Calculate the equilibrium constant at 25.0°C for each of the following reactions from the value of AG° given. (a) H2(g) + Br_() → 2 HBr(9) AG° = -106.7 kJ/mol K = (b) 1,(s) + Cl2(g) → 2 ICI(g) AG = -10.9 kJ/mol K = (c) CS5(g) - CS (0) AG° = -1.9 kJ/mol K= (d) 4 NO2(g) + O2(g) → 2 N20 (9) AG° = 29.2 kJ/mol K = (e) Sno,(s) + 2 C1 (9) - SCI,CO) + O2(9) AG°...
2. Calculate K for the reaction: IC (g) at 298 K CH,(g) + 3Cl2(g) = CHCI;(8) + 3HCI(g) at 2 A/Gº(CH.(g)) = -50.72 kJ/mol A,Gº(CHCI (g)) = -71.1 kJ/mol AG°(HCl(g)) --95.30 kJ/mol 10-14 at 25 °C. Find the value of K, 3. For the following chemical equilibrium, Kp = 4.6 x 10-14 at 25 for this reaction at 25 °C. 2012(g) + 2 H2O(g) = 4 HCI(g) + O2(g)
7 Consider the following reaction at 298 K: NH3(g) +HCI(g)NH4CI(s) Using the thermochemical data at 298 K given below (a) Determine the AH for the reaction. (2 marks) (b) Determine the AG for the reaction and comment on its value. (3 marks) (c) Determine the maximum work done available in the reaction. (3 marks) An equilibrium mixture, consisting of 0.5 atm of NHy(), 0.5 atm of HCKg) and excessive of NH Cl(s), is enclosed in a container at 298 K...
Using the reduction potentials given, calculate the equilibrium constant, K, at 20 degrees C for the reaction Using the reduction potentials given, calculate the equilibrium constant, K, at 25°C for the reaction, 33 3+ Ag (aa) t Fe(a)Ag) Fe (aq) +0.77 V +0.80 V A Ag+(aq) + e- ← a. 1.66 b. 6.4 c. 3.2 d. 6.1 x 10-4 e. 1.6 x 104 Rank the following compounds according to increasing solubility in water. K” is a less than sign) 34...
Calculate the free energy AG at 25°C for the nonstandard conditions at point where the reaction quotient Q is 2.75 x 10 Express your answer numerically in kilojoules. View Available Hint(s) % ALC O ? AG - CO Nitrosyl chloride formation Chlorine gas. Cl(s), reacts with nitric oxide, NO(), to form nitrosyl chloride, NOCI(g), via the reaction Cl(s) + 2NO(g) + 2NOCI() The thermodynamic data for the reactants and products in the reaction are given in the following table: Substance...
6) Calculate the equilibrium constant K at 25°C for the following reaction for tant K at 25°C for the following reaction for the standard cell potential (7 points) (nFEⓇ - RT In K, F=96485 C/mol.R=8.31 J/molk) Pb2+ (aq) + Fe(s) 5 Pb(8) + Fe²(aq) 7) Calculate the cell potential of the following cell at 25°C. (7 points) Fe(s) | Fe*(aq) (1.1 M) || Cu?" (aq) (0.50 M) Cu() Ecell - Eºcell = 0.0592/n logQ
problem #9 Calculate the equilibrium constant for the following reaction at 25°C. 2H2(g) + O2(g) 2H20cv) Given the following standard free-energy: H2O , -237.2 KJ/mol at 25°C. Problem #10. Given the following data at 25°C: substance sº (J/mol.K) AH', (KJ/mol) 240.45, 33.8 304.33 9.66 NO 249) N2O160) (a) Calculate the value of A Gº for the following reaction at 25°C: 2 NO2(9) N20 (9) (b) Is the formation of NO a spontaneous process at 25°C and standard-state conditions? (a) What...