QUESTION 12 Given that AG for NH=-16.667999999999999 kJ/mol, calculate the equilibrium constant for the following reaction...

Question

Question

Answer 1

Answer #1

T = 298 K

ΔGo = -16.668 KJ/mol

ΔGo = -16668 J/mol

use:

ΔGo = -R*T*ln Kc

-16668 = - 8.314*298.0* ln(Kc)

ln Kc = 6.7276

Kc = 8.351*10^2

Answer: b

Answer 2

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