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1. Consider a second-order mechanical system as shown below in Figure i. 77n Frictionless support Figure 1 Using Matlab, gene
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Answer #1

Given tral Forcing funda- impulse es AppAy

MATLAB code is given below in bold letters.

clc;
close all;
clear all;


% problem a
m = 1; b = 2;
k =[3 10 100 1000];

% define complex frequency variabel s
s = tf('s');
% plot the impulse response for various values of k
for i = 1:length(k)
X = 1/(m*s^2+b*s+k(i)); % transfer function
% now plot the impulse response
figure(1);
impulse(X);hold on;grid on;
end
legend('k = 3','k = 10','k = 100','k = 1000');


% problem b
m = 1; k = 1;
b =[0.02 0.2 0.5 2];

% define complex frequency variabel s
s = tf('s');
% plot the impulse response for various values of b
for i = 1:length(b)
X = 1/(m*s^2+b(i)*s+k); % transfer function
% now plot the impulse response
figure(2);
impulse(X);hold on;grid on;
end
legend('b = 0.02','b = 0.2','b = 0.5','b = 2.0');


% problem c
m = [1 10 50]; k = 1;
b = 2;

% define complex frequency variabel s
s = tf('s');
% plot the impulse response for various values of m
for i = 1:length(m)
X = 1/(m(i)*s^2+b*s+k); % transfer function
% now plot the impulse response
figure(3);
impulse(X);hold on;grid on;
end
legend('m = 1','m = 10','m = 50');

Impulse Response 0.3 ㅡㅡㅡㅡ k = 10 0.25 k=100 k 1000 0.2 0.15 0.1 0.05 0.05 -0.1 L 0 4 Time (seconds) 2 6

Impulse Response b 0.02 b 0.2 b -0.5 b 2.0 0.8 0.6 0.4 a 0.2 -0.2 0.4 0.6 0.8 20 30 40 Time (seconds) 0 10 50 60 70

Impulse Response 0.4 0.35 0.3 0.25 a 0.2 兰 0.15 40.1 0.05 0 0.05 0.1 m=50 100 150 Time (seconds) 0 50 200 250 300

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