If there are 3 buckets, each with 3 balls: 1 red, 1 blue, and 1 white. If one ball is randomly selected from each bucket, what is the probability of:
a) getting exactly 2 white balls
b) getting at least 2 blue balls
c) getting 3 white balls
d) getting at least 1 red ball
a)as probability of white balls frm a bucket=(1/3)
getting exactly 2 white balls=3C2(1/3)2*(2/3)1 =2/9
b)
P(getting at least 2 blue balls)=P(2 blue balls )+P(3 blue balls)=3C2(1/3)2*(2/3)1 +3C3(1/3)3*(2/3)0 =(2/9)+(1/27)=7/27
c)
P(getting 3 white balls)=3C3(1/3)3*(2/3)0 =1/27
d)
P(getting at least 1 red ball)=1-P(no red ball)=1-(2/3)3 =19/27
If there are 3 buckets, each with 3 balls: 1 red, 1 blue, and 1 white. If one ball is randomly se...
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