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Complefe the following: problem Parameters/notes Change the load: Dead -10 psf. Live - 30 psf hint: first trace the load W to

5.2 A 10 × 20 hotel marquee hangs from two rods in- clined at an angle of 30°. The dead load and snow load on the marquee a5.8 A reinforced concrete column is 12 feet long, and un- der load, it shortensinches. Determine its average unit strain.

Complefe the following: problem Parameters/notes Change the load: Dead -10 psf. Live - 30 psf hint: first trace the load W to the ends of the rods, then draw a FBD of the beam and rod and solve for reactions at C and B. Use this info to find the force in the rod. Your answer should be the diameter of a round rod rounded to 1/8" increment). Change the load to 400,000 Ibs See Appendix table A3 for Steel shape properties for your selection for part (a). As shown 5.2 5.3 5.8
5.2 A 10' × 20' hotel marquee hangs from two rods in- clined at an angle of 30°. The dead load and snow load on the marquee add up to 100 psf. Design the two rods out of A36 steel that has an allowable tensile stress: Ft- 22,000 psi (allowable stress) STEEL FRAME 5.3 A short steel column supports an axial compressive load of 120,000# and is welded to a steel base plate resting on a concrete footing a. Select the lightest W8 (wide-flange) section to use if the unit stress is not to exceed 13,500 psi. b. Determine the size of the base plate (square) required if the allowable bearing on concrete is 450 psi. c. Calculate the required size of footing (square) if the allowable soil pressure is equal to 3,000 psf Neglect weights of column, base plate, and footing.
5.8 A reinforced concrete column is 12 feet long, and un- der load, it shortensinches". Determine its average unit strain.
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Solution 5. 9 Given that Tauo sods înclined at an angde 30 Pree bodj diagram sleel tie nod 30 0 By using forsmuda, ue on ColcCalculate the force in the stel tie Tod we can take moment abaut the aus line c where lo o TAelok The fosce in the Steel tie20,00s Calculate the diamt of the single lee tie vod: Bsin the formula d diameter 049 i - tto da o 160 in fte Sie siee od tee5-9 5.3 Co) Stress on stee Coleumn is 오 12o,ooo 2 1350 8.888 in Tp ω secton for which area s 849e in RA3 Suits the eceed. (b)5-8) Given that Length of the reinforced Concele Coloumn a L1aft Tha ave-rage unit Stvain of the colcum here By using this kn

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