You have a 5 meter length of copper wire. The diameter of the wire is 0.5 mm Copper has a resistivity of p = 1.70*10^-18 ohms at room temperature.
A) What is the resistance of the wire?
B)Suppose you connect the wire to a battery, and shape the circuit to one circular loop. Sketch what the magnetic field looks like in this scenario. Include direction of current.
C) What is the magnetic field at the center of the loop. The battery is 3.00 V
D) Now consider coiling the wire so there are many, many, turns. Sketch what the magnetic field looks like in this scenario.
E) What is the magnetic field inside the coil if there are 500 turns that span 25 cm (20 turns/cm)? This is as densely as you can pack the turns.
F) A typical weak refrigerator magnet is about 5 * 10^-4 T and can pick up a paperclip. Could the coil from part E pick up a paperclip? If not, what are some things you can change to make it pick up a paperclip? If it can pick up a paperclip, what are some things you can do to increase its strength?
You have a 5 meter length of copper wire. The diameter of the wire is 0.5 mm Copper has a resisti...
A 22.0-cm-diameter coil consists of 30 turns of circular copper wire 2.8 mm in diameter. A uniform magnetic field, perpendicular to the plane of the coil, changes at a rate of 9.35×10−3 T/s . The resistivity of copper is 1.68×10−8Ω⋅m. Determine the current in the loop. Determine the rate at which thermal energy is produced.
A 30.0 cm diameter coil consists of 37 turns of cylindrical copper wire 2.40 mm in diameter. A uniform magnetic field, perpendicular to the plane of the coil, changes at a rate of 9.50 x 10-3 T/s. Determine the current in the loop in milli-amps (the resistivity for copper is 1.72 x 10-8 Ω.m).
A copper wire makes up a 139 turns, 5.60 cm diameter coil. The resistance of the coil is 3.40 Ω. There is a magnetic field parallel to the axis of the coil. If the induced current in the coil is 2.20 A, what is the rate of change of the magnetic field?
A 25 cm diameter tangent galvanometer consists of 15 turns of 0.5 mm diameter copper wire and has a current of 2 A running through it. Calculate the total internal resistance of the wire and the magnetic field at the center of the loop. (The resistivity of copper is p = 1.69 x 10-8 ohm meter).
A 20.8 cm -diameter coil consists of 30 turns of circular copper wire 2.4 mm in diameter. A uniform magnetic field, perpendicular to the plane of the coil, changes at a rate of 7.64×10−3 T/s . PART A: Determine the current in the loop. PART B: Determine the rate at which thermal energy is produced.
You have 10 m of 0.46 mm -diameter copper wire and a battery capable of passing 14 A through the wire. What magnetic field strength could you obtain inside a 2.8cm -diameter solenoid wound with the wire as closely spaced as possible? What magnetic field strength could you obtain at the center of a single circular loop made from the wire?
A 24.0-cm diameter coil consists of 45 turns of circular copper wire 3.0 mm in diameter. A uniform magnetic field, perpendicular to the plane of the coil, changes at a rate of 7.85×10−3 T/s . The resistivity of copper is 1.68×10−8Ω⋅m. Determine the current in the loop. (Express your answer to two significant figures and include the appropriate units.) Determine the rate at which thermal energy is produced. (Express your answer to two significant figures and include the appropriate units.)
A 24.0-cm diameter coil consists of 45 turns of circular copper wire 3.0 mm in diameter. A uniform magnetic field, perpendicular to the plane of the coil, changes at a rate of 7.85×10−3 T/s .The resistivity of copper is 1.68×10−8Ω⋅m. a) Determine the current in the loop. (Express your answer to two significant figures and include the appropriate units.) b) Determine the rate at which thermal energy is produced.(Express your answer to two significant figures and include the appropriate units)
A 22.0-cm-diameter coil consists of 28 turns of circular copper wire 2.6 mm in diameter. A uniform magnetic field, perpendicular to the plane of the coil, changes at a rate of 8.65 * 10 -3 T / s . Determine: the rate at which thermal energy is produced ans: _ W
2. A 0.800 mm diameter copper wire makes up a 108 turns, 8.30 cm diameter coil. There is a magnetic field parallel to the axis of the coil. If the induced current in the coil is 5.00 A, what is the rate of change of the magnetic field? A. 7.30×10-6 T/s B. 880. T/s C. 8.15 T/s D. 0.0785 T/s 3. A 11.0 mH inductor makes the current drop from 151 mA to 62.0 mA in only 6.00 μs. What...