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M 3: (20 points) Design the stirrup spacing for the beam shown below. Change your design between ...
Concrete design Problem #2: Determine the appropriate shear reinforcement required for the beam shown (spacing of...
Concrete design
Problem #2: Determine the appropriate shear reinforcement required for the beam shown (spacing of stirrups). Do not consider different loading cases for live loads and the dead load shown includes the beam's weight. Assumere 4000 psi, fy-60000 psi, and use # 3 U-shaped stirrups Note: Divide the beam into segments, 36" each where appropriate. 20k () 30k(L) 0-4 255 sy 5 #10
A rectangular beam having b=16 in and d=26 in spans 28 ft face to face of...
A rectangular beam having b=16 in and d=26 in spans 28 ft face
to face of simple supports. It is reinforced for flexure with 6#11
bars that continue uninterrupted to the ends of the span. It is to
carry service dead load 2.0 kips/ft (including self weight) and
service live load 3.6 kips/ft, both uniformly distributed along the
span. Design the shear reinforcement using vertical U stirrups.
Economize the spacing of stirrups in appropriate number of bands.
Material strengths are...
Problem 1. (40 pts) Here is a design for a beam as shown in Figs Check...
Problem 1. (40 pts) Here is a design for a beam as shown in Figs Check if this section can resist the following loading conditions in the beam according to ACI-318. Use fc -4000 psi and fy - 60,000 psi. Assume that the clear cover is 1.5" (typical) for all and the vertical spacing between #8 bars is 1 inch. Both End (L Center (L2) #8 bars #8 Stirrup #3@ 8" 8#8 bars 20 in Stirrup: 6# 8 bars Pu=15...
2. The beam in the figure below is to carry 1.6 kips/ft live load and 0.90...
2. The beam in the figure below is to carry 1.6 kips/ft live load and 0.90 kip/ft dead load (including beam weight). Using f: 3000 psi and fy 40,000 psi, investigate the beam for stirrup adequacy according to the approximate ACI method、 li design is not adequate, indicate what revision is necessary. Symmetrical about E span E60 4"」 22" 3ー#7 12" supports 12" # 3 stirrups 9"l___. 9 @ 6" 22'-0" Figure 2: Problem 2.
HW 3-1 6-9 The beam shown in Fig. P6-9 supports the unfactored D 1.4 kips/f L...
HW 3-1 6-9 The beam shown in Fig. P6-9 supports the unfactored D 1.4 kips/f L -1.5 kips/ft loads shown. The dead load includes the weight o the beam. (a) Draw shearing-force diagrams for 25 ft factored dead and live load on the entire beam; Fig. P6-9 (b) Design stirrups. Use f 4500 psi and No. 3 40,000 psi. double-leg stirrups with f 36 14* 12-
1. A rectangular beam with b 16 in., d-17 in., and h 20 in. has a clear span of 24 ft. as shown b...
1. A rectangular beam with b 16 in., d-17 in., and h 20 in. has a clear span of 24 ft. as shown below. The beam has 1 ft. of bearing at each end, so for analysis purposes it is treated as a 25 ft. simple span (to center of bearing at each end). The beam supports an unfactored concentrated live load of P-65 kips. The beam is reinforced with 6-#10 longitudinal bars and #4 stirrups. Material strengths are fc-4,000,...
NOTE Vn(min)= 12.8k Vn(Max)= 81.9k 2) Design the stirrups for the beam using f'4000 psi concrete and # 3 Grade 60 s...
NOTE
Vn(min)= 12.8k
Vn(Max)= 81.9k
2) Design the stirrups for the beam using f'4000 psi concrete and # 3 Grade 60 stirrups. a) Determine if and where no stirrups can be used in the beam. b) Provide 3 "zones" of stirrups: maximum permissible spacing near midspan, tightest spacing near the support and a transition zone 12 in f4000 psi d 16 in 24 ft #3 stirrups Normal weight concrete 3/4 in. max. aggregate 1.5 in. clear cover 2.69 in 3...
The T-beam shown in Figure 1 supports the un-factored dead load of 1.4 kips/ft and live...
The T-beam shown in Figure 1 supports the un-factored dead load
of 1.4 kips/ft and live load of 1.5 kips/ft. The dead load does not
include the self-weight of the beam. The material properties are as
follows: fc’=3000 psi; fy=60,000 psi. Design the shear
reinforcement (stirrups). Plot the stirrups distribution along the
span of the beam.
DL= 1.4 kips/ft ; L2=1.5 kips/Ft * 75 Sz=7 X * b=3616. hr-6in k ) انا امه hw-lain + * bw=12 in
Determine if the beam shown in the figure is adequate as governed by the ACI Code (318-11). The l...
Determine if the beam shown in the figure is adequate as
governed by the ACI
Code (318-11). The loads shown are service loads. The uniformly
distributed load is DL =
0.65 + 0.F = _________ kip/ft, LL = 0.55 + 0.E = ________
kip/ft. The dead load excludes
the beam weight. The point load is a live load. f’c = 3,000 psi,
fy = 40,000 psi.
Assume that all variables A,B,C,D,E,F,G are 3.5
kips (LL) 20A"= 20 + D= -...
Design a rectangular simple supported beam to carry service loads of 1.05 kips/ft of dead load...
Design a rectangular simple supported beam to carry service loads of 1.05 kips/ft of dead load (DL) (self-weight included) and 2.47kip/ft live load (LL) on a span length of 18 ft. The beam is limited to be (due to architectural reasons) 10” wide with an overall depth of 20”. Use f’c= 3,000 psi and fy= 40,000psi. Design the longitudinal reinforcement (flexure design) and the web reinforcement (Stirrups).
Concrete design
Problem #2: Determine the appropriate shear reinforcement required for the beam shown (spacing of stirrups). Do not consider different loading cases for live loads and the dead load shown includes the beam's weight. Assumere 4000 psi, fy-60000 psi, and use # 3 U-shaped stirrups Note: Divide the beam into segments, 36" each where appropriate. 20k () 30k(L) 0-4 255 sy 5 #10
A rectangular beam having b=16 in and d=26 in spans 28 ft face
to face of simple supports. It is reinforced for flexure with 6#11
bars that continue uninterrupted to the ends of the span. It is to
carry service dead load 2.0 kips/ft (including self weight) and
service live load 3.6 kips/ft, both uniformly distributed along the
span. Design the shear reinforcement using vertical U stirrups.
Economize the spacing of stirrups in appropriate number of bands.
Material strengths are...
Problem 1. (40 pts) Here is a design for a beam as shown in Figs Check if this section can resist the following loading conditions in the beam according to ACI-318. Use fc -4000 psi and fy - 60,000 psi. Assume that the clear cover is 1.5" (typical) for all and the vertical spacing between #8 bars is 1 inch. Both End (L Center (L2) #8 bars #8 Stirrup #3@ 8" 8#8 bars 20 in Stirrup: 6# 8 bars Pu=15...
2. The beam in the figure below is to carry 1.6 kips/ft live load and 0.90 kip/ft dead load (including beam weight). Using f: 3000 psi and fy 40,000 psi, investigate the beam for stirrup adequacy according to the approximate ACI method、 li design is not adequate, indicate what revision is necessary. Symmetrical about E span E60 4"」 22" 3ー#7 12" supports 12" # 3 stirrups 9"l___. 9 @ 6" 22'-0" Figure 2: Problem 2.
HW 3-1 6-9 The beam shown in Fig. P6-9 supports the unfactored D 1.4 kips/f L -1.5 kips/ft loads shown. The dead load includes the weight o the beam. (a) Draw shearing-force diagrams for 25 ft factored dead and live load on the entire beam; Fig. P6-9 (b) Design stirrups. Use f 4500 psi and No. 3 40,000 psi. double-leg stirrups with f 36 14* 12-
1. A rectangular beam with b 16 in., d-17 in., and h 20 in. has a clear span of 24 ft. as shown below. The beam has 1 ft. of bearing at each end, so for analysis purposes it is treated as a 25 ft. simple span (to center of bearing at each end). The beam supports an unfactored concentrated live load of P-65 kips. The beam is reinforced with 6-#10 longitudinal bars and #4 stirrups. Material strengths are fc-4,000,...
NOTE
Vn(min)= 12.8k
Vn(Max)= 81.9k
2) Design the stirrups for the beam using f'4000 psi concrete and # 3 Grade 60 stirrups. a) Determine if and where no stirrups can be used in the beam. b) Provide 3 "zones" of stirrups: maximum permissible spacing near midspan, tightest spacing near the support and a transition zone 12 in f4000 psi d 16 in 24 ft #3 stirrups Normal weight concrete 3/4 in. max. aggregate 1.5 in. clear cover 2.69 in 3...
The T-beam shown in Figure 1 supports the un-factored dead load
of 1.4 kips/ft and live load of 1.5 kips/ft. The dead load does not
include the self-weight of the beam. The material properties are as
follows: fc’=3000 psi; fy=60,000 psi. Design the shear
reinforcement (stirrups). Plot the stirrups distribution along the
span of the beam.
DL= 1.4 kips/ft ; L2=1.5 kips/Ft * 75 Sz=7 X * b=3616. hr-6in k ) انا امه hw-lain + * bw=12 in
Determine if the beam shown in the figure is adequate as
governed by the ACI
Code (318-11). The loads shown are service loads. The uniformly
distributed load is DL =
0.65 + 0.F = _________ kip/ft, LL = 0.55 + 0.E = ________
kip/ft. The dead load excludes
the beam weight. The point load is a live load. f’c = 3,000 psi,
fy = 40,000 psi.
Assume that all variables A,B,C,D,E,F,G are 3.5
kips (LL) 20A"= 20 + D= -...
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