Question

In a qualitative analysis procedure, a chemist adds HCI to an unknown group of ions


In a qualitative analysis procedure, a chemist adds HCI to an unknown group of ions and then saturates the solution with H2S so that the solution is 0.4 M in HCI and 0.10 M in H2

(a) What is the [HS-] of the solution? (Note: The answer should be rounded to one significant figure. Be careful, 3.5 rounds up to 4, but 4.5 rounds down to 4) 

(b) If 0.01 M of each of the following ions is in the solution, which will form a precipitate? (Select all that apply.)

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Answer #1

a)

Given data,

[H+] = 0.4 M

[H2S] = 0.1 M

We know that,

Ka of H2S = 1 x 10-7

Let us consider a reaction,

H2S ------> H+ + HS-

HS- = Ka[H2S] / [H+]

= 1 x 10-7 x 0.1 / 0.4

HS- = 2.5 x 10-8

b)

Pb2+ and Cu2+ ions will precipitate

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