Part B. Improved Power System Connected to a Parallel Load Capacitor The power factor pf (0.87914...
For parallel loads given, with load 2 is inductive (L), while load 3 is capacitive (C). Find the total a. average power, b. reactive power, c. apparent power, d. overall power factor pf of the network given. Load | 1 Load 2 Load 3 V = 220 V 20° O VAR 100 W 700 VAR (L) 200 W 1500 VAR (C) 300 W 10
P3- A source supplies power to the following three load connected in parallel: (1) a light load drawing 20 kW, (2) an induction motor drawing 10 KVA at 0.90 power factor lagging, and (3) a synchronous motor operating at 10 hp, 85% efficiency and 0.95 power factor leading (1 hp = 0.746 kW), Determine the real, reactive, and apparent power delivered by the source. Also, draw the source power triangle.
P3- A source supplies power to the following three load connected in parallel: (1) a light load drawing 20 kW. (2) an induction motor drawing 10 kVA at 0.90 power factor lagging, and (3) a synchronous motor operating at 10 hp, 85% efficiency and 0.95 power factor leading (1 hp = 0.746 kW). Determine the real, reactive, and apparent power delivered by the source. Also, draw the source power triangle.
8. (15 points) Assume we have a 100 kVA load with power factor pf= 0.8 lagging, and would like to correct the pf to 0.95 leading, please fill the following blanks: The real power before power factor compensation is The real power after power factor compensation is The reactive power before power factor compensation is The reactive power after power factor compensation is kW kW kVAR kVAR
A 240V three phase power system supplies two loads in parallel: Load 1: measured line current 30A, power factor 0.85 lagging, and Load 2: measured power 10kW, reactive power -7.5kVar A. Determine the power factor of load 2. B. Determine the total real power (in kW), reactive power (in kVAR), apparent power (in kVA), power factor and line current (in A) of the two loads.
Figure 2.6 depicts this circuit as a voltage source applied to a resistor and inductor in parallel (disregard the capacitor for part A), which is to be an equivalent to the load. Why is a resistor and inductor in parallel used for the load versus just using a resistor? Find the following (show calculations): Real power absorbed by the load. Apparent power of the load. Reactive power of the load. Don’t use the tangent function. Instead, find the reactive power using the apparent...
(a) A 240 V 50 Hz factory electrical system has the following loads connected in parallel: Load 1: 4 kW at a power factor of 0.8 lag Load 2: 6 kVA at a power factor of 0.6 lag Load3: 6.5 kVA with 2.5 kVAr of leading reactive power Determine: (C) the overall system power factor, (ii) the value of a power-factor correction capacitor to improve the power factor to unity, and (ii) the value of a power-factor correction capacitor to...
P 5.75 Part A Loads A and B are connected in parallel across a 1.kV ms 60-Hz ine, as shown in the figure below (Figure 1). Load A consumes 20 k W with a 90-percent- power factor. Load B has an apparent power of 30 kVA with an 80-percent-lagging power factor Find the power delivered by the source Express your answer to three significant figures and include the appropriate units P,-1 Value Units Figure 1of 1 Submit Request Answer line...
A single-phase electrical load draws 1000KVA at 0.8 power factor lagging. a) Find the real and reactive power absorbed by the load. b) Draw the power triangle. c) Determine the KVAR of a capacitor to be connected across the load to raise the power factor to 0.95.
A three-phase load of 15 kVA with a PF of 0.8 lagging is connected in parallel with a three-phase load of 36 kW at 0.6 PF leading. The line-line voltage is 2000V. a) Find the total complex power and power factor. Is it inductive or capacitive? b) How much kVAR is needed to make the PF unity? c) What is the magnitude of the current going into the total load?