b1^ | se(b1^) | t | lower | upper |
0.776504 | 0.064996 | 1.76131 | 0.662025 | 0.890982 |
3.972153 | 5.34589 |
formula
b1^ | se(b1^) | t | lower | upper |
0.7765036 | 0.064996 | =T.INV.2T(0.1,14) | =A2-C2*B2 | =A2+C2*B2 |
=6*D2 | =6*E2 |
hence
(3.972,5.346)
third last option is correct
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