ASSEMBLY RISCV a)Use the lui and addi instructions to store the value of 8000in x6, and then use the addi instruction to calculate the value of 8000-10 and store the result in x5 b) Use the lui an...

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a)Use the lui and addi instructions to store the value of 8000in x6, and then use the addi instruction to calculate the value

ASSEMBLY RISCV

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Answer 1

Answer #1

LUI will left shift 16 bits and thus will hold higer bytes and ADDI will the remaining 16 bits to the register.

a.

lui x6, 0x0000 # 8000 = 0x00001F40

addi x6, x6, 0x1F40 # loading 8000 in x6

addi x5, x6, 0xFFFFFFF6 # -10 = 0xFFFFFFF6, x5 stores addition of 8000 and -10

b.

lui x6, 0x0000 # 23456 = 0x00005BA0

addi x6, x6, 0x5BA0 # loading 23456 in x6

lui x7, 0x0000 # 12345 = 0x00003039

addi x7, x7, 0x3039 # loading 12345in x6

sub x5, x6, x7 # x5 stores addition of 23456 - 12345

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Answer 2

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Add Answer to: ASSEMBLY RISCV a)Use the lui and addi instructions to store the value of 8000in x6, and then use the addi instruction to calculate the value of 8000-10 and store the result in x5 b) Use the lui an...

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Add Answer to:
ASSEMBLY RISCV a)Use the lui and addi instructions to store the value of 8000in x6, and then use the addi instruction to calculate the value of 8000-10 and store the result in x5 b) Use the lui an...