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just do 4 , 3 is solved
3. Use a Bilinear Transform to design a Butterworth low-pass filter which satisfies the filter specifications: Pass band: -1S
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Answer #1

Ray band 2.0 lo- 0.125% stop band J21T 0.5 0.35 = 0.2198vn BLT 2. tan -2- . 0.12.57 0219O.22 2-1 . 5038 b. 89125 0.5038 0.01 5.97 1.1589(リ 2- O. 8912.5

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just do 4 , 3 is solved 3. Use a Bilinear Transform to design a Butterworth low-pass filter which satisfies the filter specifications: Pass band: -1Ss0 for 0sf s0.2 Stop band: (e/40 for 0.35sf s0....
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