a)
One sided t test
H0; mu = 185
Ha: mu < 185
b)
test statistics;
t = (xbar -mu)/(s/sqrt(n)))
= ( 168.9 - 185)/(26.3/sqrt(6))
= -1.499
df = 6 -1 = 5
c)
p value = P(t < -1.499)
P value = 0.0970
Fail to reject H0 as p value > 0.01
d)
The t value at 99% confidence interval is,
alpha = 1 - 0.99 = 0.01
alpha/2 = 0.01/2 = 0.005
t(alpha/2,df) = t(0.005,5) = 4.032
Margin of error = E =z *(s/sqrt(n))
= 4.032 *(26.3/sqrt(6))
= 43.2913
CI = mean +/- E
= 168.9+/- 43.2913
= (125.61 , 212.19)
The 99% CI is (125.61 , 212.19)
In this preliminary study at a level of significance of α-001 wa below 185 on the average? The deviation is, s 26.3. Assume the data is normally 5) after e mean cholesterol after the study is x=1...
6) It has been study. One een levels of treatment for the new drug will be used in the 2 study. One group will be administered the new phase of the drug once per day and a second group twice per day. You select two SRSs of 19 and 21 individuals who have been diagnosed as having high n diagnosed adrug twice per administered the new drug once per dayad cholest total cholesterol. Results are summarized in the table below....
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1. 2. E Question Help Use the sample data and confidence level given below to complete parts (a) through (d) A research institute poll asked respondents if they felt vulnerable to identity theft. In the pol, m :-020 and 503 who said yes. Use 99%。。fdence level Click the icon to view a table of z scores. a) Find the best point estimate of the population proportion p (Round to three decimal places as needed.) Click to select your answer(s) Previous...
Assume that the differences are normally distributed. Complete parts (a) through (d) below. 1 4 5 Observation X 2 47.2 3 43.6 6 45.6 7 48.2 8 49.6 42.3 46.4 47.9 Y 45.5 46.4 45.7 50.5 50.4 45.7 49.4 49.7 (a) Determine d; = X; - Yfor each pair of data. 1 2 3 4 5 6 7 8 Observation d (Type integers or decimals.) (b) Computed and sa d= (Round to three decimal places as needed.) Sd = (Round...
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