Evaluate JJD VE2 + y2 dA, where D is the domain in Figure 4 -R FIGURE 4 JDv dA 39200.29257 Evaluate JJD VE2 + y2 dA, where D is the domain in Figure 4 -R FIGURE 4 JDv dA 39200.29257
The answer is neither 1152π nor 1008π (1 point) Vx2 +y2 dA, where D is the domain in Figure 4 I Evaluate F D G:(x- 6)2y2 = 36 Fx2y2 = 144 -R R¢ -R Rf 12 Rg = 6 FIGURE 4 Slp Vx2 +y dA = 1008pi (1 point) Vx2 +y2 dA, where D is the domain in Figure 4 I Evaluate F D G:(x- 6)2y2 = 36 Fx2y2 = 144 -R R¢ -R Rf 12 Rg = 6 FIGURE...
Evaluate the integral /R (x2 + y2) dA where R is the quarter disk of radius 3 centered at the origin in the fourth quadrant of the xy-plane. Provide your answer below
Q4: Use polar coordinates to evaluate x2 - y2 dA, where R is the region in the first V9- quadrant within the circle x2 + y2-9.
Evaluate the triple integral on the given domain -2 + y2 + z2 dxdydz R where R = {{x,y,z):15 x2 + y2 +z39,85 0, y = 0, 220}
9. (10 points) Evaluate S SR(2x2 - xy - y2)dA, where R is the region bounded by y = -2x +4, y = -2x + 7, y = x - 2, and y = 1 +1.
3 attempts left Check my work Evaluate J. (2++y+8) + y2 + 8) da, where R is the circle of radius 4 centered at the origin. The answer is C R
1. (4 points) Evaluate the double integral on the given domain D xy where D={(x,y):25x54,15ys3} 2. (4 points) Evaluate the double integral on the given domain S dxdy © 1(x2 + y2)3 where D=(x,y):15x2 + y2 <4, yzo}
Evaluate // e-(x+vº)dA where D = {(x,y): x2 + y2 <1,1 20, y 2 0}.
Evaluate (*V19x2 + 19y2 dA, where D is the shaded region enclosed by the lemniscate curve r = sin(20) in the figure. r2 = sin 20 0.5 os (Use symbolic notation and fractions where needed.) «V19x + 19da = 0 Use cylindrical coordinates to find the volume of the region bounded below by the plane z = 3 and above by the sphere x2 + y2 + 2 = 25. (Use symbolic notation and fractions where needed.) V =
Evaluate the integral Sf. 313x + 3y dA where the region R is given by the figure with a = 3 and b = 5. (Assume the curved boundary of the figure is circular with center at the origin.) S IR ŽV3x2 + 3y2 dA = (125sqrt(3)/2)tan^(-1)(3/4)