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The velocity at time t seconds of a ball launched up in the air is v(t)32t 104 feet per second. Complete parts a and b. a. Find the displacement of the ball during the time interval 0sts3. The displa...
A projectile is launched from ground level with an initial velocity of v 0 feet per...
A projectile is launched from ground level with an initial velocity of v 0 feet per second. Neglecting air? resistance, its height in feet t seconds after launch is given by s equals negative 16 t squared plus v 0 t. Find the? time(s) that the projectile will? (a) reach a height of 80 ft and? (b) return to the ground when v 0 is 32 feet per second. ?(a) Find the? time(s) that the projectile will reach a height...
If a ball is thrown straight up into the air with an initial velocity of 95 ft/s, it height in feet after t second is given by y=95t–16t2
If a ball is thrown straight up into the air with an initial velocity of 95 ft/s, it height in feet after t second is given by y=95t–16t2. Find the average velocity for the time period begining when t=1 and lasting(i) 01 seconds: (ii) 001 seconds:(iii) 0001 seconds:Finally based on the above results, guess what the instantaneous velocity of the ball is when t=1.
If an object is thrown with a velocity of v feet per second at an angle...
If an object is thrown with a velocity of v feet per second at an angle of θ with the horizontal, then its flight can be modeled by, x = (v cos θ ) t and y = v (sin θ ) t - 16 t2 + h where t is in seconds and h is the object's initial height in feet above the ground. x is the horizontal position and y is the vertical position, and - 16 t2...
A projectile is launched straight up in the air. Its height (in feet) t seconds after...
A projectile is launched straight up in the air. Its height (in feet) t seconds after launch is given by the function () - 162? + 3021 5. Find its velocity 0.9 seconds after it is launched Its velocity is If necessary, round to two decimal places. Do not include units.
An object is propelled upward at an initial velocity of 32 feet per second at an...
An object is propelled upward at an initial velocity of 32 feet per second at an initial elevation of 48 feet above the ground. The free-fall model used to describe the motion is: s(t) = -1672 + 32t +48 for 03033 (t seconds from release of object). Reference: Drop the Ball Activity The average velocity between t = 2 sec and t = 3 sec A) -48 feet per second B) -24 feet per second C) 16 feet per second...
A ball is thrown vertically upward with an initial velocity of 48 feet per second.
A ball is thrown vertically upward with an initial velocity of 48 feet per second. The distances (in feet) of the ball from the ground after t seconds is s=48-16t2. (a) At what time t will the ball strike the ground? (b) For what time t is the ball more than 32 feet above the ground?
A ball is thrown vertically upward with an initial velocity of 96 feet per second
A ball is thrown vertically upward with an initial velocity of 96 feet per second. The distance s (in feet) of the ball from the ground after t seconds is s(t)=96t-16t^2a.) at what time will the ball strike the groundb.) for what time t is the ball more than 128 feet above the ground?c.) when will the ball reach its highest peak? how high is it above the ground?
A projectile is launched straight up from ground level with an initial velocity of v0 per...
A projectile is launched straight up from ground level with an initial velocity of v0 per sec. Neglecting air resistance, its height in feet, s, after t seconds after launch is given by the equation s = –16t2 + v0t. At what time(s) will the projectile reach a height of 112 feet when v0 = 96 feet/sec? After how many seconds will it return to the ground when v0 = 96 feet/sec?
3. A baseball is projected upward form the top of 448 foot tall bulding with an initial velocity of 48 feet per second. The distance s of the baseball from the ground at any time t, in seconds, i...
3. A baseball is projected upward form the top of 448 foot tall bulding with an initial velocity of 48 feet per second. The distance s of the baseball from the ground at any time t, in seconds, is glven by the equation s-16r2 +48t+448 How long will it take the ball to hit the ground? a. b. How high will the ball be in 6 seconds? When will the ball be 448 feet in the air? c. d. If...
Velocity of a Maglev The velocity (in feet per second) of a maglev is v(t) =...
Velocity of a Maglev The velocity (in feet per second) of a maglev is v(t) = 0.6t + 4 (Osts 120). At t = 0, it is at the station. Find the function f(t) giving the position of the maglev at time t, assuming that the motion takes place along a straight stretch of track. f(t) =
A projectile is launched straight up in the air. Its height (in feet) t seconds after launch is given by the function () - 162? + 3021 5. Find its velocity 0.9 seconds after it is launched Its velocity is If necessary, round to two decimal places. Do not include units.
An object is propelled upward at an initial velocity of 32 feet per second at an initial elevation of 48 feet above the ground. The free-fall model used to describe the motion is: s(t) = -1672 + 32t +48 for 03033 (t seconds from release of object). Reference: Drop the Ball Activity The average velocity between t = 2 sec and t = 3 sec A) -48 feet per second B) -24 feet per second C) 16 feet per second...
3. A baseball is projected upward form the top of 448 foot tall bulding with an initial velocity of 48 feet per second. The distance s of the baseball from the ground at any time t, in seconds, is glven by the equation s-16r2 +48t+448 How long will it take the ball to hit the ground? a. b. How high will the ball be in 6 seconds? When will the ball be 448 feet in the air? c. d. If...
Velocity of a Maglev The velocity (in feet per second) of a maglev is v(t) = 0.6t + 4 (Osts 120). At t = 0, it is at the station. Find the function f(t) giving the position of the maglev at time t, assuming that the motion takes place along a straight stretch of track. f(t) =
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