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An overhanging steel beam is used to carry a uniformly distributed load over a 2-metre length as shown. The yield stress of steel is ơyield-350 MPa. Check if the cross section of the beam at section...
Question 3 For the simply supported steel beam with cross section and loading shown (see Figure...
Question 3 For the simply supported steel beam with cross section and loading shown (see Figure 3a), knowing that uniformly distributed load w=60 kN/m, Young modulus E = 200 GPa, and yield stress Cyield=200 MPa (in both tension and compression). ул 15 mm w=60 kN/m ... 1 B A 15 mm + 300 mm IC - i 2.5m 1 1 15 mm 7.5m 1 150 mm Figure 3a (a) Check if: the beam is safe with respect to yielding (using...
The below wooden double overhanging beam is under a uniformly distributed load W. The wood is...
The below wooden double overhanging beam is under a uniformly distributed load W. The wood is weak along the orientation of the grain (or wood cell fibres) that makes an angle of 30° with the horizontal (see figure). The maximum shear stress on a plane parallel to the grain that the wood can sustain is t,max = 5 MPa, and the maximum normal stress of wood is omax = 25 MPa. The Young modulus of this wood is E=15 GPa....
The simply-supported beam having I-beam cross-section as shown in figure is to carry a uniformly distributed...
The simply-supported beam having I-beam cross-section as shown in figure is to carry a uniformly distributed load over its entire 1.2m length. Specify the maximum allowable load if the beam is made from malleable iron, ASTM A220, class 80002. The allowable tensile stress is 164 MPa and allowable compressive stress is 412 MPa. The centroid of the section is located at 35 mm from the bottom and moment of inertia are Ix = 2.66 x 10 mm". (a) Draw loading...
A low carbon steel shaft is designed to have a diameter of 30 mm. It is...
A low carbon steel shaft is designed to have a diameter of 30 mm. It is to be subjected to an axial load (P-30 kN), a moment (M-200 N-m), and a torque (T-300 N-m). Assume the yield stress for the steel is (280 MPa), the Poisson's ratio is (v= 0.29), and the safety factor is (1-1). Calculate the margin of safety using the following failure theories. a.) Rankine Criteria (Maximum Principal Stress) b.) Tresca Criteria (Maximum Shear Stress) c.) Saint...
The bar is made of mild steel (Sy =245 MPa) and is loaded by the forces...
The bar is made of mild steel (Sy =245 MPa) and is loaded by the forces Fx = 300 N, F, = 450 N, F2 = 300 N, and Mx = 55 N m. - 100 mm (A) Find the principal stresses and the max shear stress at A of the member. (B) Compute the von Mises stress at A. TINTI (C) Compute the factors of safety of the member using the distortion-energy (DE) and maximum-shear-stress (MSS) theories. 15-mm D....
As shown in Figure 8, the structural member (beam) is 7m long, carries a 2 kN point load, a 1.2 kN/m uniformly distribu...
As shown in Figure 8, the structural member (beam) is 7m long, carries a 2 kN point load, a 1.2 kN/m uniformly distributed load and is supported at points A and B. The beam is constructed from two pieces of steel plate (2 at 80mm x 8mm) that are welded together with 3mm welds. Section properties for the beam are also listed. Given the support reactions as RAv 5.8 kN and RBv 2.2 kN, as well as the shear force...
7.26 Torking stress in either tension or compression is AMS. 92.8 mm x 185.6 mm o MPa. am 3 m long is simply supported at each end and carries a uniformly distributed load of 10 kN/m. The beam...
7.26
Torking stress in either tension or compression is AMS. 92.8 mm x 185.6 mm o MPa. am 3 m long is simply supported at each end and carries a uniformly distributed load of 10 kN/m. The beam at rectangular cross section, 75 mm x 150 mm. Determine the magnitude and location of the peak bending ress. Also, find the magnitude of the bending stress at a point 25 mm below the upper surface at the section midway betwcen supports....
56.5 Mpa The internal shear force V at a certain section of a steel beam is...
56.5 Mpa
The internal shear force V at a certain section of a steel beam is 80 kN, and the moment of inertia is 64,867,500 mm. Determine the horizontal shear stress at point H, which is located L = 55 mm below the centroid. 15 mm 80 KN 10 mm 210 mm 210 mm O 41.0 MPa 48.5 MPa O 29.3 MPa O 37.1 MPa 56 5 MD
Q2 A simply supported beam of length L = 10 m carries a uniformly distributed load...
Q2 A simply supported beam of length L = 10 m carries a uniformly distributed load w of 10 kN/m, as shown in Figure Q2 (a). The beam is made from a symmetrical I-section and consists of three equal rectangular members of 100 mm x 10 mm (see Figure Q2 (b)). Self- weight of the beam is neglected. 100 mm w = 10 kN/m A- - A 100 mm 77777 L/3 L/3 L/3 — Figure Q2 (a) Figure Q2 (b)...
QI A cantilever steel beam of length L 7.5 m carries both a uniformly distributed load...
QI A cantilever steel beam of length L 7.5 m carries both a uniformly distributed load w of 20 kN/m throughout its length and a point load P of 10 kN at its free end, as shown in Figure QI (a). The beam is made from a rectangular hollow box section with a width of 300 mm and a depth of 450 mm (refer to Figure Q1 (b)). The wall thickness of the box section is constant throughout which is...
Question 3 For the simply supported steel beam with cross section and loading shown (see Figure 3a), knowing that uniformly distributed load w=60 kN/m, Young modulus E = 200 GPa, and yield stress Cyield=200 MPa (in both tension and compression). ул 15 mm w=60 kN/m ... 1 B A 15 mm + 300 mm IC - i 2.5m 1 1 15 mm 7.5m 1 150 mm Figure 3a (a) Check if: the beam is safe with respect to yielding (using...
The below wooden double overhanging beam is under a uniformly distributed load W. The wood is weak along the orientation of the grain (or wood cell fibres) that makes an angle of 30° with the horizontal (see figure). The maximum shear stress on a plane parallel to the grain that the wood can sustain is t,max = 5 MPa, and the maximum normal stress of wood is omax = 25 MPa. The Young modulus of this wood is E=15 GPa....
The simply-supported beam having I-beam cross-section as shown in figure is to carry a uniformly distributed load over its entire 1.2m length. Specify the maximum allowable load if the beam is made from malleable iron, ASTM A220, class 80002. The allowable tensile stress is 164 MPa and allowable compressive stress is 412 MPa. The centroid of the section is located at 35 mm from the bottom and moment of inertia are Ix = 2.66 x 10 mm". (a) Draw loading...
A low carbon steel shaft is designed to have a diameter of 30 mm. It is to be subjected to an axial load (P-30 kN), a moment (M-200 N-m), and a torque (T-300 N-m). Assume the yield stress for the steel is (280 MPa), the Poisson's ratio is (v= 0.29), and the safety factor is (1-1). Calculate the margin of safety using the following failure theories. a.) Rankine Criteria (Maximum Principal Stress) b.) Tresca Criteria (Maximum Shear Stress) c.) Saint...
The bar is made of mild steel (Sy =245 MPa) and is loaded by the forces Fx = 300 N, F, = 450 N, F2 = 300 N, and Mx = 55 N m. - 100 mm (A) Find the principal stresses and the max shear stress at A of the member. (B) Compute the von Mises stress at A. TINTI (C) Compute the factors of safety of the member using the distortion-energy (DE) and maximum-shear-stress (MSS) theories. 15-mm D....
As shown in Figure 8, the structural member (beam) is 7m long, carries a 2 kN point load, a 1.2 kN/m uniformly distributed load and is supported at points A and B. The beam is constructed from two pieces of steel plate (2 at 80mm x 8mm) that are welded together with 3mm welds. Section properties for the beam are also listed. Given the support reactions as RAv 5.8 kN and RBv 2.2 kN, as well as the shear force...
7.26
Torking stress in either tension or compression is AMS. 92.8 mm x 185.6 mm o MPa. am 3 m long is simply supported at each end and carries a uniformly distributed load of 10 kN/m. The beam at rectangular cross section, 75 mm x 150 mm. Determine the magnitude and location of the peak bending ress. Also, find the magnitude of the bending stress at a point 25 mm below the upper surface at the section midway betwcen supports....
56.5 Mpa
The internal shear force V at a certain section of a steel beam is 80 kN, and the moment of inertia is 64,867,500 mm. Determine the horizontal shear stress at point H, which is located L = 55 mm below the centroid. 15 mm 80 KN 10 mm 210 mm 210 mm O 41.0 MPa 48.5 MPa O 29.3 MPa O 37.1 MPa 56 5 MD
Q2 A simply supported beam of length L = 10 m carries a uniformly distributed load w of 10 kN/m, as shown in Figure Q2 (a). The beam is made from a symmetrical I-section and consists of three equal rectangular members of 100 mm x 10 mm (see Figure Q2 (b)). Self- weight of the beam is neglected. 100 mm w = 10 kN/m A- - A 100 mm 77777 L/3 L/3 L/3 — Figure Q2 (a) Figure Q2 (b)...
QI A cantilever steel beam of length L 7.5 m carries both a uniformly distributed load w of 20 kN/m throughout its length and a point load P of 10 kN at its free end, as shown in Figure QI (a). The beam is made from a rectangular hollow box section with a width of 300 mm and a depth of 450 mm (refer to Figure Q1 (b)). The wall thickness of the box section is constant throughout which is...
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