Pre-requisite Formulas
ES = EF of Preceding activity (0 for source task), highest to be selected
EF = ES + Activity Time of the tasks
LF = LS of succeeding activity (Critical path time for Sink Task), lowest to be selected
LS = LF - Activity Time of the tasks
Answer-
The Network flow diagram along with the Early Start (ES), Early Finish (EF), Late Start (LS) and Late Finish (LF) is as shown in the diagram-
To identify the critical path, we will first identify those tasks which has ES=LS and EF=LF. The tasks A,F,G.D & J are the tasks adhering to this criteria and hence, constitute the critical path. Therefore the critical path is A-F-G-D-J.
The scheduled project duration is = Sum of tasks in critical path = 90+25+14+20+45 = 194 days
Time taken by Non Critical paths-
A-F-G-D-E = 90+25+14+20+21 = 170 days
A-F-G-D-H = 90+25+14+20+28 = 177 days
A-B-C-G-D-E = 90+15+5+14+20+21 = 165 days
A-B-C-G-D-H = 90+15+5+14+20+28 = 172 days
A-B-C-G-D-J = 90+15+5+14+20+45 = 189 days
A-I-J = 90+30+45 = 165 days
B) The management wants to bring the project 8 days before the scheduled period. Therefore, the critical activities needs to be crashed by 8 days.
Calculating Improvement factor for all activity using formula - Improvement factor = (Crash Cost - Normal Cost)/(Normal Time - Crash Time)
Activity | Normal Time | Normal Cost | Crash Time | Crash Cost | Improvement Factor |
A | 90 | 2250 | 85 | 2520 | 54 |
B | 15 | 180 | 13 | 210 | 15 |
C | 5 | 90 | 4 | 120 | 30 |
D | 20 | 300 | 16 | 340 | 10 |
E | 21 | 231 | 17 | 315 | 21 |
F | 25 | 250 | 22 | 375 | 41.66666667 |
G | 14 | 70 | 12 | 112 | 21 |
H | 28 | 392 | 25 | 448 | 18.66666667 |
I | 30 | 510 | 28 | 570 | 30 |
J | 45 | 1350 | 41 | 1530 | 45 |
Highlighted are the critical activities.
From the above table we see that, out of the critical activities,
the Improvement factor of Activity D is least and should be crashed
first. On crashing Activity D, we shall get a reduction in project
duration of 4 days.
Now, we see that the Improvement factor of Activity G is the next lowest figure and should be crashed second. On crashing Activity G, we shall get a reduction in project duration of 2 days. Thus resulting in the total project duration reduction to 6 days.
Now, we see that the Improvement factor of Activity F is the next lowest figure and should be crashed third. On crashing Activity F, we shall get a reduction in project duration of 3 days. Thus resulting in the total project duration reduction to 9 days.
Therefore, the critical path duration after crashing will now be = 90+22+12+16+45 = 185 days
Time taken by Non Critical paths-
A-F-G-D-E = 90+22+12+16+21 = 161 days
A-F-G-D-H = 90+22+12+16+28 = 168 days
A-B-C-G-D-E = 90+15+5+12+16+21 = 159 days
A-B-C-G-D-H = 90+15+5+12+16+28 = 166 days
A-B-C-G-D-J = 90+15+5+12+16+45 = 183 days
A-I-J = 90+30+45 = 165 days
As the non-critical paths still have time duration less than the critical path, the critical path doesn't change on crashing.
C) To achieve the desired time of project completion, the management has to undergo the above stated crashing steps. This crashing would subsequently also increase the investment required for project completion. Based on the investment capabilities, the management should decide how much early they should target to release the product as compared to the normal scheduled time. Nevertheless, evaluating the steep increase of Improvement factor in the third crashing step, the management should stop crashing at the second step itself. The monetary investment required to undertake the third crashing doesn't justify the extent to which it bring reduction in project duration. Therefore, the product should be launched at 188th day rather than on 186th, if monetary investment is given highest precedence.
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