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Problem Set 1: The independent-samples t test Research Scenario: A learning psychologist is interested in comparing the success of two different mnemonics (memorization methods) on performance in a me...

Problem Set 1: The independent-samples t test

Research Scenario: A learning psychologist is interested in comparing the success of two different mnemonics (memorization methods) on performance in a memory task. He assigns students to two groups, one which learns and uses a language-based rhyming memory technique, and one which learns and uses a visual “method of loci” spatial memory technique. He then administers a memory task to each group of students. The students are scored based on the percentage of correct answers.   

Using this table, enter the data into a new SPSS data file and run an independent-samples t test to test the claim that there is a difference in the percentage of correct answers between the two groups. Follow the directions below the table to complete the homework.

Language-Based

Spatially-based

   93

   77

   89

   87

   78

   62

   67

   90

   95

83

89

72

95

76

63

99

84

93

Group Statistics

Groups

N

Mean

Std. Deviation

Std. Error Mean

Scores

Language_Based

9

82.0000

11.69402

3.89801

Spatially_Based

9

83.7778

11.73433

3.91144

Independent Samples Test

Levene's Test for Equality of Variances

t-test for Equality of Means

F

Sig.

t

df

Sig. (2-tailed)

Mean Difference

Std. Error Difference

95% Confidence Interval of the Difference

Lower

Upper

Scores

Equal variances assumed

.051

.825

-.322

16

.752

-1.77778

5.52212

-13.48415

9.92860

Equal variances not assumed

-.322

16.000

.752

-1.77778

5.52212

-13.48416

9.92861

  1. Write an APA-style Results section based on your analysis. Include your boxplot as an APA-style figure as demonstrated in the APA writing presentation. (Results = 8 pts; Graph = 5 pts) (Just need this one answered please. Its urgent!)
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Answer #1

We have conducted independent t-test to compare the means

we see that test statistic is -0.322 and p-value is 0.752

since p-value is less than significance level

we fail to reject the null hypothesis

we conclude that there is not sufficient evidence to support the claim that there is a difference in the percentage of correct answers between the two groups.

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