I need Help Plz in java
search trees in Java
Design an algorithm that converts any search tree into an AVL tree
in linear time pleas with comments. You can assume that the search
tree 2k-1. k ∈ N, Knot owns
class BST( object ):
def __init__( self ):
self.root = None
def getRoot( self ):
return self.root
def DSW( self ):
if None != self.root:
self.createBackbone() # effectively: createBackbone( self.root)
self.createPerfectBST() # effectively: createPerfectBST( self.root)
#=====================================================================
# Time complexity: O(n)
#=====================================================================
def createBackbone( self ):
grandParent = None
parent = self.root
leftChild = None
while None != parent:
leftChild = parent.left
if None != leftChild:
grandParent = self.rotateRight( grandParent, parent, leftChild )
parent = leftChild
else:
grandParent = parent
parent = parent.right
#=======================================================================
# Before After
# Gr Gr
# \ \
# Par Ch
# / \ / \
# Ch Z X Par
# / \ / \
# X Y Y Z
#=======================================================================
def rotateRight( self, grandParent, parent, leftChild ):
if None != grandParent:
grandParent.right = leftChild
else:
self.root = leftChild
parent.left = leftChild.right
leftChild.right = parent
return grandParent
#=======================================================================
# Time complexity: O(n)
#=======================================================================
def createPerfectBST( self ):
n = self.size()
# m = 2^floor[lg(n+1)]-1, ie the greatest power of 2 less than n: minus 1
m = self.greatestPowerOf2LessThanN( n + 1 ) - 1
self.makeRotations( n - m )
while m > 1:
m /= 2
self.makeRotations( m )
#=======================================================================
# Time complexity: log(n)
#=======================================================================
def greatestPowerOf2LessThanN( self, n ):
x = self.MSB( n ) # MSB
return ( 1 << x ) # 2^x
#=======================================================================
# Time complexity: log(n)
# return the index of most significant set bit: index of
# least significant bit is 0
#=======================================================================
def MSB( self, n ):
ndx = 0
while 1 < n:
n = ( n >> 1 )
ndx += 1
return ndx
def makeRotations( self, bound ):
grandParent = None
parent = self.root
child = self.root.right
while bound > 0:
try:
if None != child:
self.rotateLeft( grandParent, parent, child );
grandParent = child;
parent = grandParent.right;
child = parent.right;
else:
break
except AttributeError: # TypeError
break
bound -= 1
def rotateLeft( self, grandParent, parent, rightChild ):
if None != grandParent:
grandParent.right = rightChild
else:
self.root = rightChild
parent.right = rightChild.left
rightChild.left = parent
PSEUDO CODE:
1.Allocate a node, the "pseudo-root", and make the tree's actual
root the right child of the pseudo- root.
2.Call tree-to-vine with the pseudo-root as its argument.
3.Call vine-to-tree on the pseudo-root and the size (number of
elements) of the tree.
4.Make the tree's actual root equal to the pseudo-root's right
child.
5.Dispose of the pseudo-root.
I need Help Plz in java search trees in Java Design an algorithm that converts any search tree into an AVL tree in linea...
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