C12H22O11(s)+8KCLO3(s)=12CO2(g)+11H2O(g)+8KCL(8) 1. If each skittle contains 0.84 g of sucrose (C12H22O11) what is the m...
C12H22O11(s)+8KCLO3(s)=12CO2(g)+11H2O(g)+8KCL(8)
1. If each skittle contains 0.84 g of sucrose (C12H22O11) what is the maximum number of skittles needed to maximize the product (no KCLO3 remaining) if i use 12.0 g of KCLO3?
2. how many grams of reactants remains (excess) after 2.5 g sucrose and 25.0 g KCLO3 react?
3. if 2.2 gram of CO2 are produced what is the precent yield?
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C12H22O11(s)+8KCLO3(s)=12CO2(g)+11H2O(g)+8KCL(8) 1. If each skittle contains 0.84 g of sucrose (C12H22O11) what is the m...
C12H22O11(s) + 8 KClO3(s) -----> 12 CO2(g) + 11 H2O(g) + 8 KCl(s) KClO3= 122.6 g/mol...
C12H22O11(s) + 8 KClO3(s) -----> 12 CO2(g) + 11 H2O(g) + 8 KCl(s) KClO3= 122.6 g/mol sucrose= 342.3 g/mol CO2= 44.01 g/mol 1 skittle= .84 grams of sucrose 1. If each skittle contains 0.84 g of sucrose (C12H22O11) What is the minimum number of skittles needed to maximize the product if I use 12.0g of KClO3? 2. How many grams of reactant remain (excess) after 2.5g of sucrose and 25.0g KClO3 react? 3. If 2.2 grams of CO2 are produced,...
C12H22O11(s) + 8 KClO3(s) -> 12 CO2(g) + 11 H2O(g) + 8 KCl(s) KClO3...
C12H22O11(s) + 8 KClO3(s) -> 12 CO2(g) + 11 H2O(g) + 8 KCl(s) KClO3 = 122.6 g/mol sucrose = 342.3 g/mol CO2 = 44.01 g/mol 1 skittle = 0.84 grams of sucrose 1. If each skittle contains 0.84 g of sucrose (C12H22O11) What is the minimum number of skittles needed to maximize the product (no KClO3 remaining) if I use 12.0 g of KClO3?
C12H22O11(s) + 8 KClO3(s) -> 12 CO2(g) + 11 H2O(g) + 8 KCl(s) KClO3 = 122.6 g/mol sucrose = 342.3 g/mol CO2 = 44.01 g...
C12H22O11(s) + 8 KClO3(s) -> 12 CO2(g) + 11 H2O(g) + 8 KCl(s) KClO3 = 122.6 g/mol sucrose = 342.3 g/mol CO2 = 44.01 g/mol 1 skittle = 0.84 grams of sucrose How many grams of reactant remain (excess) after 2.5 g sucrose and 25.0 g KClO3 react?
C12H22O11(s) + 8 KClO3(s) -> 12 CO2(g) + 11 H2O(g) + 8 KCl(s) KClO3 = 122.6...
C12H22O11(s) + 8 KClO3(s) -> 12 CO2(g) + 11 H2O(g) + 8 KCl(s) KClO3 = 122.6 g/mol sucrose = 342.3 g/mol CO2 = 44.01 g/mol 1 skittle = 0.84 grams of sucrose ** 17.85 (g) remaining of KCLO3- reactant ** 5 skittles from sucrose If 2.2 grams of CO2 are produced, what is the percent yield?
Consider the reaction C12H22O11(s)+12O2(g)→12CO2(g)+11H2O(l) in which 10.0 g of sucrose, C12H22O11, was burned in a bomb...
Consider the reaction C12H22O11(s)+12O2(g)→12CO2(g)+11H2O(l) in which 10.0 g of sucrose, C12H22O11, was burned in a bomb calorimeter with a heat capacity of 7.50 kJ/∘C. The temperature increase inside the calorimeter was found to be 22.0 ∘C. Calculate the change in internal energy, ΔE, for this reaction per mole of sucrose. Express the change in internal energy in kilojoules per mole to three significant figures.
1a) Consider the reaction: C12H22O11(s)+12O2(g)→12CO2(g)+11H2O(l) in which 10.0 g of sucrose, C12H22O11, was burned in a...
1a) Consider the reaction: C12H22O11(s)+12O2(g)→12CO2(g)+11H2O(l) in which 10.0 g of sucrose, C12H22O11, was burned in a bomb calorimeter with a heat capacity of 7.50 kJ/∘C. The temperature increase inside the calorimeter was found to be 22.0 ∘C. What is the heat of this reaction per mole of sucrose? 1b) One tablespoon of peanut butter has a mass of 17.0 g. It is combusted in a calorimeter whose heat capacity is 110 kJ/°C. The temperature of the calorimeter rises from 21.6...
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Sodium hydroxide reacts with carbon dioxide as follows: 2 NaOH(s) + CO2(g) Na2CO3(s) + H2O(1) If 3.70 mol NaOH and 2.00 mol CO2 are allowed to react, how many moles of the excess reactant remains? 0.15 mol CO2 O 0.30 mol NaOH O 1.70 NaOH 1.00 mol CO2 How much energy is required to change the temperature of 1.50 L of water from 25.0 °C to 100.0 °C? The specific heat capacity of water is 4.184 J/g.°C; density H2O =...
CHEM 1033, Sample Exam II (Homework) Chapters 3,4,6 Name: 1. What volume of 0.132 M KOH...
CHEM 1033, Sample Exam II (Homework) Chapters 3,4,6 Name: 1. What volume of 0.132 M KOH solution would react completely with 25.8 ml. of 0.198 M HCl according to the following cquation? HCI+KOH --->KCI+H.O a) 86.4 ml. b) 25.7 ml. c) 38.7 ml d) 17.2 ml. 2. Which one of the following is a strong soluble base? a) Ni(OH): b) Mg(OH): c) RLOH d) ChOH) c) Fe(OH) 3. Which one of the following is a strong acid? a) HF b)...
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Sodium hydroxide reacts with carbon dioxide as follows: 2 NaOH(s) + CO2(g) Na2CO3(s) + H2O(1) If 3.70 mol NaOH and 2.00 mol CO2 are allowed to react, how many moles of the excess reactant remains? 0.15 mol CO2 O 0.30 mol NaOH O 1.70 NaOH 1.00 mol CO2 How much energy is required to change the temperature of 1.50 L of water from 25.0 °C to 100.0 °C? The specific heat capacity of water is 4.184 J/g.°C; density H2O =...
CHEM 1033, Sample Exam II (Homework) Chapters 3,4,6 Name: 1. What volume of 0.132 M KOH solution would react completely with 25.8 ml. of 0.198 M HCl according to the following cquation? HCI+KOH --->KCI+H.O a) 86.4 ml. b) 25.7 ml. c) 38.7 ml d) 17.2 ml. 2. Which one of the following is a strong soluble base? a) Ni(OH): b) Mg(OH): c) RLOH d) ChOH) c) Fe(OH) 3. Which one of the following is a strong acid? a) HF b)...
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