Question

2 Figure 6

You are given a circuit with a resistor, an inductor and a capacitor as shown in Figure 6. Based on the analysis of 2nd Order Transient Response and using circuit simulator software (e.g. P-Spice, LT-Spice, Multisim etc.)

Answer 1

Solution InrtiaV Values 2 2- R. dt R dt dt2 LC LC 2RC ル 2Rc

2x 0-2 0 5 m2t m,t -0.505七 -4142t «NOW &r t-o > 0 3 41426 e dt dt-

dt SSSA e 341420e FM 3-4142 t Ure

0.8st 34142t .0.yo69 e t 0.7069 e dt -3 41y2t -3 41y2t 1.2067 e 0 Tlovo - 3.4/4it -3.yn t) _ | 0.206ヲe 0:206fe 206e I-4)38e 14138 e - 0 2 06 e t-206 e -1413D e -34142七 0.20e Verifying the results for Fi for inductor current: Put t in above equation we get ( 0.20 Which is same as we assumed hefore

INDUCTOR_RATED Label Display Value Pins Animation slowdown factor: PR1 Coil resistance: C1 L1 R1 Current rating (Pk): 10 MH 0.5Ω Initial conditions: CAPACITOR RATED Label Display Value Pins Animation slowdown factor: 0.5 Capacitance 50 Voltage rating (Pk) Circuit diagram with specfied initial conditions using Multisim Initial conditions:

Analyses and Simulation Active Analysis: Interactive Simulation Transient Analysis paremeters DC Operating Point s optons Analyss parameters Output Analysis optons Summary AC Sweep Initial condtions User-defned Variables in crcuit: variables for analysis: Transient All variables Al TSTART): 0 DC Sweep N(vc) Single Frequency AC End 20 Parameter Sweep Maximum time step (TMAX): Determine automatically Noise Add Setting a smal TMAX value wil improve accuracy, however the simulation time will nareaso Monte Carlo Remove Fourler Initial time step (TSTEP): Determine automatically Temperature Sweep Edit Distortion Go to 'output' tab and Worst Case add variables Pole Zero Transfer Function Trace Width Reset to default Click Run Bun Help Transient Simulation settings using MULTISIM

Design1 Transient 1.2 0.8 Current response 0.6 o 0.2 0.0 0.2 Voltage response 0.6 16 4 12 20 Time (s) V(vc) PR1) Transient response curve obtained using multisim