Question

425.8 mal CO N2H ()+O2 (g) NO2 (g) +H2O (g). NZH4 302 2NOZ ZAZO a. If 75.0 kg of hydrazine reacted with 75.0 kg of oxygen, which is the limiting reagent?

Answer 1

Page 1 O. (a) If 75.0kg of hydrazine reacted with 75.0 kg of oxygen which is the limiting reagent? N,44() +30, (g) — INQ (0) + 24,068) (Hydrazine) - (oxygen) - (7500 kg , (750 kg ) ear To find the limiting reagent, we will follow written below. a convert the reagents listed from grams to moles. a out how many moles of products we can form out with calculated moles of reagents. Cing Find out which reagent is completely used up, and that will be our limiting reagent. nining reagent, we will follow the procedure we can do all this in one step, 75x10² g (Hydrazine) x t mole (hydjazine) x 2 mole (NO₂) 32.045 g (hydrazine) I mole (hydrazine) = 0 mole 4.68 X10 of No₂ Similary, 75 K 20° (g) (he) x 3 mole (oxygen) x 2 mole (NO2) = 14.06x10² 32 g ( ₂ ) 3 mole (02) mole of No2. (oxygen) supporting information! Molar mass of N = 32.045 g/mol Molar mass of Ę (3) = 32 g/mol

page-2 now, 4.68X10² < 19.06x103 at the end of From Name from ą (g) (hydrazine) reaction So all of hydrazine (N₂14) will react completely A and hence Naha (hydrazine) is the limiting reagent in this reaction. Limiting reagent a The limiting reagent is the reagent that will be used up completely , this limiting the extent of the reaction .