I just need help with the last question on here, the one highlighted in red. Given that K, for HCIO is 4.0 x 10' at...

Question

Question

I just need help with the last question on here, the one highlighted in red.

Given that K, for HCIO is 4.0 x 10 at 25°C, what is the value of Kh for CIO at 25°C? Ko= 25x107 Given that K, for (CH), N is

Answer 1

Answer #1

The complete step wise calculation is given as below:-

Answer 2

Similar Homework Help Questions

Given that K, for HF is 6.3 x 10-4 at 25 °C, what is the value...

Given that K, for HF is 6.3 x 10-4 at 25 °C, what is the value of Ky for Fat 25 °C? Given that Kt, for (CH), N is 6.3 x 10- at 25 °C, what is the value of K, for (CH), NH+ at 25 °C? Ka =
Given that K, for HBrO is 2.8 x 10-9 at 25 °C, what is the value...

Given that K, for HBrO is 2.8 x 10-9 at 25 °C, what is the value of Ký for BrO at 25 °C? Kb = Given that Ký for (CH,),N is 6.3 x 10-5 at 25 °C, what is the value of K, for (CH,),NH+ at 25 °C? K =
Given that K, for HCN is 6.2 x 10-10 at 25 °C, what is the value...

Given that K, for HCN is 6.2 x 10-10 at 25 °C, what is the value of Ky for CN- at 25 °C? Given that Kh for CH, NH, is 5.0 x 10-4 at 25 °C, what is the value of K, for CHNHĨ at 25 °C? Kg =

at 25 °C, what 5 Given that K, for HF is 6.3 x 10 value of...

at 25 °C, what 5 Given that K, for HF is 6.3 x 10 value of K for F at 25 °C? Given that Ki for NH, is 1.8 x 10" at 25 °C, what value of K, for NH at 25 °C?
I just need help with those marked with a red X, and the last question thank...

I just need help with those marked with a red X, and the last question thank you! Problem 15-08 (Algorithmic) Refer again to the gasoline sales time series data in the following table. Week Sales (1000s of gallons) a. Using a weight of 1/2 for the most recent observation, 1/3 for the second most recent, and 1/6 for third most recent, compute a three-week weighted moving average for the time series. Use rounded for two decimal places values for intermediate...
I just want to clarify what I need help on (as I do not need help...

I just want to clarify what I need help on (as I do not need help on the full question). Specifically what I want is to be able to set the equations given to me so that I can solve for n using a root finding algorithm (which I already have). As I understand, I need something of the form | Tn(x) - e^x | = epsilon machine = (x^(n+1) / (n+1)!) and all I need from there is to...

i just need 103 & 105 please explain fully 15.103. Predict which solution in each pair...

i just need 103 & 105 please explain fully 15.103. Predict which solution in each pair below will have the a. 1.25 X 10" M HNO3 or 1.00 x 10" M NaOH higher pH. b. 0.345 mM HBrO (PK. = 8.64) or 0.345 mM HCIO 45 mM Be(OH)2 (K = 5 x 10-1) or 45 mM Ba(OH)2 (K. = 2.9 X 10-8) c. d. 1.6 mm (pKs = 8.03) or 0.60 mM (pK6 = 8.32) e. 1.67 X 10-3 M...
i need help woth this!! Part A K. From the value Ke = 1.2 x 10°...

i need help woth this!! Part A K. From the value Ke = 1.2 x 10° for Ni(NH3).2+, calculate the concentration of NH3 required to just dissolve 0.024 mol of NiC 04 (K,p = 4 x 10-1) in 1.00 L of solution. (Hint: You can neglect the hydrolysis of C,0,2- because the solution will be quite basic.) Express your answer using two significant figures. Iyo AEO ? (NH3) = 0.37 M Submit Previous Answers Request Answer
TABLE 15.5 Acid lonization Constants (K) for Some Monoprotic Weak Acids at 25 °C Acid Formula...

TABLE 15.5 Acid lonization Constants (K) for Some Monoprotic Weak Acids at 25 °C Acid Formula Structural Formula lonization Reaction К. pk, = -log (2) Chlorous acid HCIO H-0-C=0 1.1 x 10-2 1.96 Stronger acids Nitrous acid HNOZ H-O-NO 5.6 x 10-4 HCIO2(aq) + H2011) = H30* (aq) + CO2 (aq) HNO2(aq) + H20(I) = H30+ (aq) + NO2 (aq) HF(aq) + H20(1) = H30* (aq) + F"(aq) 3.25 Hydrofluoric acid HF H-F 6.3 x 10-4 3.20 O Methanoic acid...

What is the pH n aqueous solution with a hydroxide ion concentration of 1.60 x 10-4...

What is the pH n aqueous solution with a hydroxide ion concentration of 1.60 x 10-4 M? O 14.2 03.80 O 10.2 0 -0.204 Consider the reaction. HF(aq) + KOH(aq) — KF(aq) + H20(1) What is the net ionic equation for the chemical reaction? HF(aq) + K+ (aq) + OH(aq) — K+(aq) + F-(aq) + H+(1) + OH-(1 HF(aq) + K+ (aq) —> K+ (aq) + H2O(l) HF(aq) + K+(aq) + OH- (aq) — K+(aq) +F-(aq) + H2O(1) HF(aq) +...