If a buffer solution is 0.120 M0.120 M in a weak acid (?a=7.5×10−5)Ka=7.5×10−5) and 0.440 M0.440 M in its conjugate base, what is the pH?
Answer
pH = 4.68
Explanation
pKa = - log Ka
pKa of weak acid = - log( 7.5 ×10-5) = 4.12
Henderson - Hasselbalch equation is
pH = pKa + log([A-]/[HA])
pH = 4.12 + log([0.440M/0.120M])
pH = 4.12 + 0.56
pH = 4.68
If a buffer solution is 0.120 M0.120 M in a weak acid (?a=7.5×10−5)Ka=7.5×10−5) and 0.440 M0.440 M in its conjugate base...
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