Question

lens 1 @ 56 cm

lens 2 @ 74.8cm

screen @ 77.5 cm

size of image 1.5 x 1.5 cm and is inverted

what would be a ray diagram dor this set ? (nswer questjon #4 pls

focal length of lens 1 =15.55cm

focal lengh of lens 2= 31.04 cm

is removed. It is as if there is a light source where the screen used to be that produces light, ie, a new "object". In the later parts of the lab, consider only the region on the track further away ее than the screen used to be. Using your knowledge of lenses as well as the focal length of lens 2, where can you put lens 2 to form another real image? Should you put lens 2 close to where the screen was, or far away? Experiment until you can form another real image of lens 2 that you can display on the screen. (Note: depending on where you place lens 2, the image may be off the end of the track) Record where you placed lens 2 and the screen.

Answer 1

CAM . will act ao au し2

euce, to obtaiu aal Leus ) 4o o btaui a 31. oA uum onu lius 3 should hilteol 33. 74 Scanne wth CamScanner

31' ουμ 少 Fi weu wnditon immage- Scanded wath

33. 14u 2 2F2 31.04 I 2 usth s Scanned with CamScanner ormed