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To determine efficiency metrics, engineers collected data for a full shift of production run on machine A. During this time:

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Answer #1

1. Machine yield = Number of good parts coming out of the system / total parts produced

= (1200-6)/1200 =0.995 =99.5%

2. Availability = run time / planned production time

Run time = 480 - ( 20+10+30+20) = 400

Availability = 400/480 = 0.8333

Performance Efficiency = Ideal cycle time x total count / run time

=0.25 x1200 /400 =0.75

2. OEE = Yield x performance x availability

= 0.995x0.833x0.75 =0.6218

The OEE can be improved by bringing about improvement in all three areas.

The machine yield can be imoroved by further reducing the number of defective products. If this is brought to 0, the yield can be 100%. The availability can be improved by minimising the time elapsed due to breakdowns ( 50 min). If it is removed completely, the new availability can be 450/480 =0.9375

The performance can be improved by producing more items per unit time, i.e. balancing the line optimally to reduce the idle time per cycle and improve efficiency. It can be improved from 75% to over 90%.

OEE if Yield is 100%, performance is 90% and availability is 0.9375.

OEE = 1 x0.9x0.9375 =0.8437

  

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