Given:
lambda = 450 nm = 4.5*10^-7 m
Find energy of 1 photon first
use:
E = h*c/lambda
=(6.626*10^-34 J.s)*(3.0*10^8 m/s)/(4.5*10^-7 m)
= 4.417*10^-19 J
This is energy of 1 photon
Energy of 1 mol = energy of 1 photon * Avogadro's number
= 4.417*10^-19*6.022*10^23 J/mol
= 2.66*10^5 J/mol
= 266 KJ/mol
For 8 moles,
E = 8 mol * 266 KJ/mol
= 2128 KJ
Answer: 2.13*10^3 KJ
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