Question

Substitution and Elimination practice problems Analyze the reactant(s) and reaction conditions, then predict the structure of the major organic product and indicate the predominant mechanism (Syl, SN2, El. or E2) of each reaction. къс(Снь. CH CH CH CH Br (сн),сон, 82с масн, CH3CH2CH2CH Br CHOH, Pc Всньсн, DMF,0°C сны + NaNO3 5°C CH, Сн,-с-отз НО 22°C CH CHOH 22°C кос(CH))). (CH)))соң, бес CHI + CHISH 43°C - месн,CH, CH,CHAOH, 78° с Н,0 22° C AB NACH CH,OH, O°C

Answer 1

&c(снэ) , Снси,сна ензен,Сн, сн. Ви (см3 ),сон , sit "halo alkane REC(Cuzz = Shong base . 4 E2 elimmation 22° - heat )

CH3CH2 CH₂ CH₂ Bv. NaOCH - CH2OH, 0°C CH3 CH 2 CH CH 2 Ome. li halalkane Na 8 CH₂ = shong nucleophile / base. I SN? 0% = dow temperature q 6o Na SCHE nila Bosching CW) you $Chesus SCH2CH3 OMF,0°C. 2-haloalkane Na SCH₂ CH3 = a strong nucleophile DME = polar aprotic solvent 0°C = dow temperature. 7 SN2 . - na | CH3 I + Nano > CH₃ NO2 SN² 8060 - CH3 H2O ! (-OTS H2C-6-OH 22°C CH3 CH3 : 3- haloalkane H20 = weak nucleophile pola prohic Solvent y - 22°c = Low temperature , 92CH3 CH3 Сизон 222 TOCH35 SN Reason: Same as the above reachion.

- CH3 88 (CH3)2 I Bv (Chalecoh, 82e 3- haloalkame. 7 ** 80*CH3)3 = shang and bulky base. 826 = high heat . EI CH31 + CHESH CHgas-cha Swz 43°C. li se bore Na CH2 CH3 CH3CH204 78°C 2. haloalkane. Na o CH₂ CH2 = shong base. 78% = heat ç Ez CH3 Z SNI 3- halo alkame H20 = week nucleophile. 22'c - dow temperature of s -Br OCH 2 Naocha, Ch 04, OĆ 1-haballame, 8CHg = shong nucleophile 3