I don't know how to do the clear function, which mean delete the nodes between n1 and n2
This is the code to perform the clear() function:
I will explain how it works now
suppose we have the linked list as 9->8->7->6->5->4->3->2->1, and we need to delete all elements between nodes that point to 9 and 3:
let us see how we delete a node from a linked list:
this is what we keep doing from n1 to n2.
9->8->7->6->5->4->3->2->1
<--------- initial list
9->7->6->5->4->3->2->1
<--------- deleted 8
9->6->5->4->3->2->1
<--------- deleted 7
9->5->4->3->2->1
<---------deleted 6
9->4->3->2->1 <--------- deleted
5
9->3->2->1 < ------ deleted 4 to get final list
Since you have not provides the test code i have only provided the function you needed. For any further assistance, please comment and if the answer helped please upvote
I don't know how to do the clear function, which mean delete the nodes between n1 and n2 # include<ios-ream>...
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