Question

The answers are in red. Please break it down for me, Thanks in advance!

Research discovered that the average heart rate of a sweeper in curling (a Winter Olympic sport) is 191 beats per minute. Assume the heart rate for a sweeper follows the normal distribution with a standard deviation of 5 beats per minute. Complete parts a through d below. a. What is the probability that a sweeper's heart rate is more than 194 beats per minute? 0.2743 (Round to four decimal places as needed.) b. What is the probability that a sweeper's heart rate is less than 187 beats per minute? 0.2119 (Round to four decimal places as needed.) c. What is the probability that a sweeper's heart rate is between 186 and 189 beats per minute? 0.1859 (Round to four decimal places as needed.) d. What is the probability that a sweeper's heart rate is between 195 and 199 beats per minute? 0.1571 (Round to four decimal places as needed.)

Answer 1

5 solution Here mean (M) = 191, S.D() = 5 a here zun-u - 194-191 = 0.6 for a=194, 2= 5. P(x7194)=P(2706) = 1-p/2206) = 1-0-7257 = (0-2743 b) for a=187, 2=187-191 _ -0-8 s = Pla2187 =P(22-0-8)= (0-2 119) c) for x = 186, 2=186-191 = -1 Tele for x=189, z = 189-191_-o.n. P ( Between 1868 189)=P(-152E-0-4) =P (22-0.4) - P(22-) = 0-304601587 = 0-1859 d) for x=195, 2=195-191_08 for x=199, 2= 199! = 16 P (Between 195 & 199)=P(0.85 2216) =P(2516)-P(220-8) = 0.9352-0-788) = 0.157)