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College of Engineering and Computing Department of Civil and Environmental Engineering CWR3201 -Fluid Mechanics Problem 1: Wa
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ge-i velo ahy of elow 2.4 mls diameter op pipe =0 mM O 5m (3) auo Kinematic visCosity .004x lo mle The charge in paessue overhge2 -> ReLative pi pe vaughnes lo-3 Por Relative Pipe Youghn ess = lo3 or o.00l and - Yenalds nomber o. 6x lo6 have rickinPage-3 Hhan Oigin o pipe Change in pressure = 2.3486 m- m 3486m deseas Cate: Due to fgichion, alwayg pressore of flou lsges b

-> Note:

In case a: due to friction, pressure head always decreases so change in pressure is head loss due to fiction.

In case b:

if elevation decreases then pressure increases by an amount of change in elevation. So in this case: change in pressure= friction loss - elevation difference.

Let p is Inifial presore in TO undlexstand his, Case Peinas e - eriin (oss final So, Change in ressure (r-exiion ss - evicHis

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