Question

6. Consider the installation for the water supply, shown in the figure where friction for the short run of pipe between the supply tank and pump can be ignored, and in which nodes 1 and 2 are essentially at the same elevation. The equation for the pressure increase (kPa) across the centrifugal pump is: Ap p2-P1 =6.895-0.002021Q2 where the unit of Q4 is liter/s. Compute the flow rates Q Qp and Qc in liter/s, and the pressures(gauge) p, P2, P, Pa and p, in kPa. Assume that the pipe lengths have already included the equivalent lengths of all fittings and valves. (20°C water) Discharge tanks 4 Z4 24 m Pipe B 5 Zs = 18 m Z3 -8 m(3 Pipe C Supply tank Pipe A Pipe L, m D, cm Z1 220 0.00523 A 25 B 90 0.00584 Pump 5 150 0.00566 CO un un

Answer 1

Anscoes the instaliation-te waliupplyp- ShRuS hoe trietron ta the Stun the Aank and Pum pe blthe. Ru at the ame which node and estenkaly aTe gral evevaon. - the Incease pressure (kpa) the Citical Pum АРЕ Pa- Pi 7 he preaure gauge) pi P2 P3 a 6.89B Ps b 0 002021 PS O O0523FB 0.00S g 4, £c 20-o0566 .

rorm otmp ieute . Ct remute the betuon aud Op Benoulles VI 2 = Y Y Oaud Zera are he vakton at PI-Parm Patm Patm patn) Yと = re lalion Re

(Area) x Vn 6.895-D-002 02 P G.e95u. (()') D 002021 6.l0112 Vi 21 595 8ubdelut ed n )- Patm 2 2 1. Sq5-5.0l12 62.4Jbl3 YoR atu Ibs/in (ty a-P) 21595e O 03611 (1-54 X1o - 5. lot2 x2 21.595 2-Sq5 25.9136 (14-7-P) o.22658 21.sq5-.436 6u ( (y.-P P 21.Sq 5-169.121Squ+J1.y 369 4P2 0 368t P2 = 146.5 265y 4.039 Ps!7

em ure !- P -gh P3 14.039 P&12.196 Danetla Ha tove pApes cole Connected o A8 A h hc PA LA QA feLco 2.xde5 12.1xd 21x das fA LAxdE o-bo523 26X 16u 2-5 O.0958 A 0.3095 A - A2 XV2

6.0506) 30 3.9 A O 3095 92 11 C k COL)eled o oo 566 (150)( 0.005y (0)(63 & C F&LBd .209 Q c t-2709 at enure Pu= Pa - Pgh (2-196 8.4 93 Prenure at = 12. 1976-6.2698 pS5.82 Pst